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3 years ago

Given g(x)=-2 find g(8+x)

Mathematics

1 answer:

grigory [225]3 years ago

5 0

26 because when 2 meets 6 it forms the number aka # 26

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If 6 cans of soup cost $1.50, how much will 9 cans cost?

Step2247 [10]

If 6 cans of soup cost $1.50

9 cans cost .......................x?

x = 9 * 1.50 / 6

x = 2.25

Answer

9 cans cost $2.25

3 0

3 years ago

Your credit card has a balance of $3300 and an annual interest rate of 14%. You decided to pay off the balance over two years. I

NARA [144]

9514 1404 393

Answer:

$137.90 more each month
$246.00 less total interest

Step-by-step explanation:

The amortization formula is ...

A = P(r/12)/(1 -(1 +r/12)^(-12t))

for the monthly payment on principal P at annual rate r for t years. Here, we have P=3300, r = 0.14, and t=1, so the monthly payment is ...

A = $3300(0.14/12)/(1 -(1 +0.14/12)^-12) ≈ $296.30

The payment of $296.30 is ...

$295.30 -158.40 = $137.90 . . . more each month

The total amount paid is 12×$296.30 = $3555.60, so 255.60 in interest. This amount is ...

$501.60 -255.60 = $246.00 . . . less total interest

3 0

3 years ago

Find $\int \dfrac{x}{\sqrt{1-x^4}}$ Please, help

ki77a [65]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2867785

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{x}{\sqrt{1-x^4}}\,dx}\\\\\\ \mathsf{=\displaystyle\int\! \frac{1}{2}\cdot 2\cdot \frac{1}{\sqrt{1-(x^2)^2}}\,dx}\\\\\\ \mathsf{=\displaystyle \frac{1}{2}\int\! \frac{1}{\sqrt{1-(x^2)^2}}\cdot 2x\,dx\qquad\quad(i)}$

Make a trigonometric substitution:

$\begin{array}{lcl}
\mathsf{x^2=sin\,t}&\quad\Rightarrow\quad&\mathsf{2x\,dx=cos\,t\,dt}\\\\
&&\mathsf{t=arcsin(x^2)\,,\qquad 0\ \textless \ x\ \textless \ \frac{\pi}{2}}\end{array}$

so the integral (i) becomes

$\mathsf{=\displaystyle\frac{1}{2}\int\!\frac{1}{\sqrt{1-sin^2\,t}}\cdot cos\,t\,dt\qquad\quad (but~1-sin^2\,t=cos^2\,t)}\\\\\\
\mathsf{=\displaystyle\frac{1}{2}\int\!\frac{1}{\sqrt{cos^2\,t}}\cdot cos\,t\,dt}$

$\mathsf{=\displaystyle\frac{1}{2}\int\!\frac{1}{cos\,t}\cdot cos\,t\,dt}\\\\\\
\mathsf{=\displaystyle\frac{1}{2}\int\!\f dt}\\\\\\
\mathsf{=\displaystyle\frac{1}{2}\,t+C}$

Now, substitute back for t = arcsin(x²), and you finally get the result:

$\mathsf{\displaystyle\int\! \frac{x}{\sqrt{1-(x^2)^2}}\,dx=\frac{1}{2}\,arcsin(x^2)+C}$ ✔

________

You could also make

x² = cos t

and you would get this expression for the integral:

$\mathsf{\displaystyle\int\! \frac{x}{\sqrt{1-(x^2)^2}}\,dx=-\,\frac{1}{2}\,arccos(x^2)+C_2}$ ✔

which is fine, because those two functions have the same derivative, as the difference between them is a constant:

$\mathsf{\dfrac{1}{2}\,arcsin(x^2)-\left(-\dfrac{1}{2}\,arccos(x^2)\right)}\\\\\\
=\mathsf{\dfrac{1}{2}\,arcsin(x^2)+\dfrac{1}{2}\,arccos(x^2)}\\\\\\
=\mathsf{\dfrac{1}{2}\cdot \left[\,arcsin(x^2)+arccos(x^2)\right]}\\\\\\
=\mathsf{\dfrac{1}{2}\cdot \dfrac{\pi}{2}}$

$\mathsf{=\dfrac{\pi}{4}}$ ✔

and that constant does not interfer in the differentiation process, because the derivative of a constant is zero.

I hope this helps. =)

6 0

3 years ago

What is the volume of a pyramid that is 11 feet tall and has a 3 foot base

marshall27 [118]

Well you would do 1/2bh, 11 x 3 is 33 so half of that is 16.5

7 0

3 years ago

Read 2 more answers

Solve for x. <br><br> 45(15x+20)−7x=56(12x−24)+6

Liula [17]

Greetings!

Solve for x.
$45(15x+20)-7x=56(12x-24)+6$
Distribute the Parenthesis.
$675x+900-7x=56(12x-24)+6$
$675x+900-7x=672x-1344+6$
Combine Like Terms.
$668x+900=672x-1338$
Add 1338 to both sides.
$(668x+900)+1338=(672x-1338)+1338$
Subtract 668x from both sides.
$[(668x+900)+1338]-668x=[(672x-1338)+1338]-668x$
Simplify.
$900+1338=672x-668x$
$2238=4x$
Divide both sides by 4.
$(2238)/4=(4x)/4$
Simplify.
$559.5=x$
$x=559.5$

Hope this helps.
-Benjamin

8 0

3 years ago

Read 2 more answers