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3 years ago

6

help pleaseeeeee !!!! i’ll give brainliest !

1 answer:

sammy [17]3 years ago

7 0

9) answer is Hypotenuse
10) opposite

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The length of a rectangle is 3 cm more than twice the width. The area of the rectangle is 65 square centimeters. Find the dimens

polet [3.4K]

Answer:

5 cm and 13 cm

Step-by-step explanation:

Let b be the width of the rectangle.

Length = 3+2b

The area of the rectangle is 65 cm²

We need to find the dimensions of the rectangle. The area of a rectangle is given by :

A = lb

$65=(3+2b)b\\\\65=3b+2b^2\\\\3b+2b^2-65=0\\\\b=5\ cm,-6.5\ cm$

Neglecting the negative value, the width of the rectangle is 5 cm.

Length = 3+2b

=3+2(5)

=3+10

=13 cm

Hence, the dimensions of the rectangle are 5 cm and 13 cm.

6 0

3 years ago

Cal added 2 3/8 cups of raisins. Write this number as a fraction greater than 1 in simplest form.

xxTIMURxx [149]

$2\frac{3}{8}=2(\frac{8}{8}) +\frac{3}{8} = \frac{16}{8} +\frac{3}{8} = \frac{19}{8}$

8 0

3 years ago

I need help finding the measure of angle one angle to an angle three

Westkost [7]

Answer:

1 and 3 are 47 degrees and 2 is 133 degrees

4 0

2 years ago

56 + -90 * 2 - -17 =

julsineya [31]

Answer: -1654

Step-by-step explanation:

4 0

3 years ago

What is the equation of the quadratic graph with a focus of (6, 0) and a directrix of y = −10 ?

Mademuasel [1]

Answer:

$(x-6)^{2}=20(y+5)^{2}$

Step-by-step explanation:

The standard for for the equation of a parabola is $(x-h)^{2}=4p(y-k)$

The focus is given as $(h, k+p)$

The directrix is given by $y=k-p$

Comparing focus given as $(6,0)$ to formula of focus $(h,k+p)$ , we see that $h=6$ and $k+p=0$
Comparing directrix given as $y=-10$ to formula of directrix $y=k-p$ , we can write $k-p=-10$

We can use the two system of equations [ $k+p=0$ and $k-p=-10$ ] to solve for $k$ and $p$ .

<em>Adding the two equations gives us:</em>

$2k=-10\\k=\frac{-10}{2}\\k=-5$

<em>Using this value of $k$ , we can find $p$ by plugging this value in either equation. Let's put it in </em><em>Equation 1</em><em>. We have:</em>

$k-p=-10\\-5-p=-10\\-5+10=p\\p=5$

Now, that we know $h=6$ , $k=-5$ , and $p=5$ , we can plug these values in the standard form equation to figure out the parabola's equation. Doing so and rearranging gives us:

$(x-6)^{2}=4(5)(y-(-5))^{2}\\(x-6)^{2}=20(y+5)^{2}\\$

This is the equation of the parabola with focus $(6,0)$ and directrix $y=-10$

3 0

3 years ago

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