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bearhunter [10]
3 years ago
11

An area of a wall is 50 in. wide and 35 in. high. Will a mirror with a 62 in. diagonal fit in it? Identify the correct explanati

on.
Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

i used the pythagorean theorem and used 50 and 35 as the legs and the diagonal as the hypotenuse

35² + 50² = c²

c² = 3725

c = \sqrt{3725}, which is 61.03

since 61.03 is less than 62" then it should fit in

lisabon 2012 [21]3 years ago
3 0

Answer:

no, a mirror with a 62 in diagonal will not fit

Step-by-step explanation:

A (area) of the wall = (50)(35) = 1750in²

find the diagonal of the wall via the pythagorean theorem:

a² + b² = c² where a = 50 and b = 35 and c = diagonal of the wall

(50)² + (35)² = c²

2500 + 1225 = c²

3725 = c²                   take the square root of both sides

c = √3725 = √25 • 149

c = 5√149 ≈ 61.03277 inches

61.03277 < 62in, so no

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