Question

An area of a wall is 50 in. wide and 35 in. high. Will a mirror with a 62 in. diagonal fit in it? Identify the correct explanation.

Answer 1

Answer:

yes

Step-by-step explanation:

i used the pythagorean theorem and used 50 and 35 as the legs and the diagonal as the hypotenuse

35² + 50² = c²

c² = 3725

c = $\sqrt{3725}$, which is 61.03

since 61.03 is less than 62" then it should fit in

Answer 2

Answer:

no, a mirror with a 62 in diagonal will not fit

Step-by-step explanation:

A (area) of the wall = (50)(35) = 1750in²

find the diagonal of the wall via the pythagorean theorem:

a² + b² = c² where a = 50 and b = 35 and c = diagonal of the wall

(50)² + (35)² = c²

2500 + 1225 = c²

3725 = c²                   take the square root of both sides

c = √3725 = √25 • 149

c = 5√149 ≈ 61.03277 inches

61.03277 < 62in, so no