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3 years ago

Which of these relations is a function?

Mathematics

1 answer:

mina [271]3 years ago

6 0

The function is in the top right

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sweet [91]

Answer:

$\boxed{x - y = -2\sqrt{7}}$

Given:

$x + y = 4 \\ \\ {x}^{2} + {y}^{2} = 22 \\ \\ {x}^{4} = {y}^{4} - 176 \sqrt{7}$

Step-by-step explanation:

$= > {x}^{4} = {y}^{4} - 176 \sqrt{7} \\ \\ = > {x}^{4} - {y}^{4} = - 176 \sqrt{7} \\ \\ = > {( {x}^{2}) }^{2} - { ({y}^{2}) }^{2} = - 176 \sqrt{7} \\ \\ = > ( {x}^{2} + {y}^{2} )( {x}^{2} - {y}^{2} ) = - 176 \sqrt{7} \\ \\ = > ( {x}^{2} + {y}^{2}) (x + y)(x - y) = - 176 \sqrt{?} \\ \\ = > 22 \times 4(x - y) = - 176 \sqrt{7} \\ \\ = > 88(x - y) = - 176 \sqrt{7} \\ \\ = > x - y = - \frac{176 \sqrt{7} }{88} \\ \\ = > x - y = - 2 \sqrt{7}$

Identity used:

${x}^{2} - {y}^{2} = (x + y)(x - y)$

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4 years ago

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Please explain your answer as well. Thx!!!

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Answer:

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Step-by-step explanation:

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