B. Add actions , such as fly ins , between slide
Answer:
it would have to be flow control which would be C.
Explanation:
Answer:
The most straight forward way to do it: in general string are zero index based array of characters, so you need to get the length of the string, subtract one and that will be the last character, some expressions in concrete languages would be:
In Python:
name = "blair"
name[len(name) - 1]
In JavaScript:
name = "blair"
name[name.length - 1]
In C++:
#include <string>
string name = "blair";
name[name.length() - 1];
Answer:
#include <iostream>
using namespace std;
void divide(int numerator, int denominator, int *quotient, int *remainder)
{
*quotient = (int)(numerator / denominator);
*remainder = numerator % denominator;
}
int main()
{
int num = 42, den = 5, quotient=0, remainder=0;
divide(num, den, "ient, &remainder);
return 0;
}
Explanation:
The exercise is for "Call by pointers". This technique is particularly useful when a variable needs to be changed by a function. In our case, the quotient and the remainder. The '&' is passing by address. Since the function is calling a pointer. We need to pass an address. This way, the function will alter the value at the address.
To sum up, in case we hadn't used pointers here, the quotient and remainder that we set to '0' would have remained zero because the function would've made copies of them, altered the copies and then DELETED the copies. When we pass by pointer, the computer goes inside the memory and changes it at the address. No new copies are made. And the value of the variable is updated.
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