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NISA [10]
3 years ago
8

Doctors sometimes use this formula to calculate how much medicine to give a child. A child who is 4 years old needs some medicin

e. The amount for an adult is 20 ml. Use the formula to work out the correct amount for this child.
Mathematics
1 answer:
AnnyKZ [126]3 years ago
5 0

Answer:

A basic formula, solving for x, guides us in the setting up of an equation: D/H x Q = x, or Desired dose (amount) = ordered Dose amount/amount on Hand x Quantity

Step-by-step explanation:

Medications are available in multiple concentrations, therefore orders written in "mL" rather than "mg" are not acceptable and require further clarification.

...

Example 2.

Step 1. Calculate the dose in mg: 18 kg × 100 mg/kg/day = 1800 mg/day

Step 2. Divide the dose by the frequency: 1800 mg/day ÷ 1 (daily) = 1800 mg/dose

You might be interested in
The ratio of hamburgers to hot dogs is 6 to 5. Three times the number of hot dogs is 6 more than twice the number of hamburgers.
Kitty [74]

Answer:the number of hot dogs is 10

Step-by-step explanation:

Let x represent the number of hamburgers.

Let y represent the number of hot dogs.

The ratio of hamburgers to hot dogs is 6 to 5. This means that the ratio of x to y is 6/5

x/y = 6/5

5x = 6y

x = 6y/5

Three times the number of hot dogs is 6 more than twice the number of hamburgers. This means that

3y = 2x + 6 - - - - - - - - -1

Substituting x = 6y/5 into equation 1, it becomes

3y = 2(6y/5) + 6

3y = 12y/5 + 6

Multiplying both sides of the equation by 5, it becomes

15y = 12y + 30

15y - 12y = 30

3y = 30

y = 30/3 = 10

x = 6y/5 = 6×10/5

x = 60/5 = 12

8 0
4 years ago
Find the value of x in the parallelogram below.
Natasha_Volkova [10]

Answer: 127 deg

Step-by-step explanation:

53+53 = 106

360-106=254

254/2 = 127

x = 127 deg

3 0
3 years ago
Read 2 more answers
I thought this was much more easier for you! :)
monitta
Problem 1)

The base of the exponential is 12 which is also the base of the log as well. The only answer choice that has this is choice B.

======================================================================
Problem 2)

log(x) + log(y) - 2log(z)
log(x) + log(y) - log(z^2)
log(x*y) - log(z^2)
log[(x*y)/(z^2)]

Answer is choice D

======================================================================
Problem 3)

log[21/(x^2)]
log(21) - log(x^2)
log(21) - 2*log(x)

This matches with choice B

======================================================================
Problem 4)

Ln(63) = Ln(z) + Ln(7)
Ln(63)-Ln(7) = Ln(z)
Ln(63/7) = Ln(z)
Ln(9) = Ln(z)
z = 9

======================================================================
Problem 5)

Ln(5x-3) = 2
5x-3 = e^2
5x = e^2+3
x = (e^2+3)/5

This means choice A is the answer
4 0
3 years ago
What is the geometric mean of 10 and 40
Varvara68 [4.7K]

the geometric mean is 20

the geometric mean of 2 numbers a and b is \sqrt{ab}

\sqrt{10(40)} = \sqrt{400} = 20


8 0
3 years ago
A researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playi
Andreas93 [3]

Answer:

Proportion of the students recalled more than 15 names is 91.77%.

Step-by-step explanation:

We are given that a researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playing the name game, the students were asked to recall as many first names of fellow students as possible.

The mean number of names recalled was 19.41 with a standard deviation of 3.17.

<em>Let X = number of names recalled</em>

SO, X ~ N(\mu = 19.41,\sigma^{2} = 3.17^{2})

The z-score probability distribution is given by ;

                  Z = \frac{X-\mu}{\sigma} } } ~ N(0,1)

where, \mu = mean number of names recalled = 19.41

            \sigma = standard deviation = 3.17

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, proportion of the students recalled more than 15 names is given by = P(X > 15 names)

     P(X > 15) = P( \frac{X-\mu}{{\sigma} } } > \frac{15-19.41}{3.17}  } ) = P(Z > -1.39)

                                                      = P(Z < 1.39) = 0.9177  {using z table}

<em>Therefore, proportion of the students recalled more than 15 names is </em><em>91.77%.</em>

4 0
3 years ago
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