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3 years ago

9

Andrea gets a monthly allowance. She first spends a fourth of her money on Target. Then, she spends $5 on food. She has $12 left

over. What is Andrea's monthly allowance?

2 answers:

zlopas [31]3 years ago

8 0

68
12+5=17
17x4= 68 gg

motikmotik3 years ago

5 0

Answer:

68

Step-by-step explanation:

12 + 5 = 17

17 x 4 = 68

Andrea's monthly allowance is $68.

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A box of peanut-butter crackers was divided evenly among 6 children. Each child got 9 crackers. How many crackers were in the bo

tia_tia [17]

You would just multiply 9x6. This gives you 54

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10. The sum of two numbers is 6 less than twice the first number. Their difference is 10 less than four times the second number.

Ilya [14]

Answer:

10 and 4.

Step-by-step explanation:

Let x be the first number.

Let y be the second number.

x + y = 2x - 6

x - y = 4y - 10

x = 4y - 10 + y

x = 5y - 10

(5y - 10) + y = 2(5y - 10) - 6

6y - 10 = 10y - 20 - 6

6y - 10 = 10y - 26

6y - 10y = -26 + 10

-4y = -16

y = 4

x - (4) = 4(4) - 10

x - 4 = 16 - 10

x - 4 = 6

x = 6 + 4

x = 10

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4 years ago

IXL problem please help

Firlakuza [10]

Answer:

IJ=JG= 20

J1=J2= 90°

HJ= HJ

SO:

HI= HG

s= 3s-54

2s= 54

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3 years ago

The product of two integers is eighty,their quotient is five.Write both integers in numerical order and separated by a comma,no

Goryan [66]

SOLUTION

Let the two integers be x and y.

Now, the product of x and y, is 80, that is

$\begin{gathered} x\times y=80 \\ xy=80\ldots\ldots\text{.equation 1} \end{gathered}$

The quotient of x and y is 5, that is

$\begin{gathered} x\div y=5 \\ \frac{x}{y}=5\ldots\ldots\ldots\ldots\text{.}\mathrm{}\text{equation 2} \end{gathered}$

From equation 2, make x, the subject, we have

$\begin{gathered} \frac{x}{y}=5 \\ \text{cross multiplying } \\ 5\times y=x \\ x=5y \end{gathered}$

Now substitute the x for 5y into equation 1, we have

$\begin{gathered} xy=80 \\ 5y\times y=80 \\ 5y^2=80 \\ \text{dividing by 5} \\ y^2=\frac{80}{5} \\ y^2=16 \\ \text{take square root of both sides } \\ \sqrt[]{y^2}=\sqrt[]{16} \\ \text{square cancels root} \\ y=4 \end{gathered}$

Now substitute y for 4 into any of the equations.

Let us use equation 1 again, we have

$\begin{gathered} xy=80 \\ x\times4=80 \\ 4x=80 \\ x=\frac{80}{4} \\ x=20 \end{gathered}$

Hence the answer is 4, 20

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1 year ago

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You can check my recent post my account explaining this problem

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3 years ago