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kondor19780726 [428]
3 years ago
14

Plssssss help me with my test

Mathematics
1 answer:
STatiana [176]3 years ago
3 0
58.5 yards







yea hope this helps
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The cup, on the 9th hole of a golf course, is located, dead center, in the middle of a circular green, which is 35 feet in radiu
ale4655 [162]

Answer:

± 27.33 ft

Step-by-step explanation:

For the given problem, we can estimate the initial and final coordinates of the line of the ball path as (-40,-50) and (0,0). Therefore, the slope is:

(-50-0)/(-40-0) = 50/40 = 1.25

Similarly, we can estimate the slope of a perpendicular line to the line of the ball path as: -1*(1/1.25) = -0.8.

Therefore, using (0,0) and the slope -0.8, the equation of the perpendicular line is: -0.8 = (y-0)/(x-0);

-0.8 = y/x

y = -0.8x

Furthermore, we are given the circle radius as 35 ft and we can use the distance formula to find the two points 35 ft far from the origin:

35^2 = x^2 + y^2

y = -0.8x

35^2 = x^2 + (-0.8x)^2

1225 = (x^2 + 0.64x^2)

1225 = 1.64x^2

x^2 = 1225/1.64 = 746.95

x = sqrt(746.95) = ± 27.33 ft

5 0
3 years ago
The Nakagin Capsule Tower has 140 modules and is 14 stories high. If all of the modules were divided evenly among the number of
schepotkina [342]
There would be 10 modules on each floor
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Whats the inequality in the graph?
Kazeer [188]

Answer:

y=2x-5

Step-by-step explanation:

Slope is rise over run, or y/x

The points given were (0,-5) and (-1,-3)

Using y2-y1/x2-x1 we can find the slope.

-3-(-5)/-1-0 = 2/-1 = -2 = slope

Next, we have to find the y-intercept. The y-intercept is where the point on the line meets the y-axis.

This point is shown at -5.

Now, putting our information into y=mx+b (slope-intercept form)

y=2x-5

2 is our slope

-5 is our y intercept

6 0
3 years ago
Solving need help in don't get it
Orlov [11]
\sqrt{3x-5}-2=0
add 2 to both sides
\sqrt{3x-5}=2
square both sides
3x-5=4
add 5 to both sides
3x=9
divide 3
x=3

a nswer is B
4 0
3 years ago
15. Ellen records the time it takes for her to commute to work on 100 consecutive mornings and finds that the times are approxim
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First one A second one C third one d 4th one E
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