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xxTIMURxx [149]
3 years ago
14

If myClass has a constructor with a parameter of type String, select the other constructor that should be included.

Computers and Technology
1 answer:
JulijaS [17]3 years ago
7 0

Answer:

d. public myClass( ) {. . .}

Explanation:

A constructor is a special method that is called when an object of a class is created. It is also used to initialize the instance variables of the given class. A class may have one or more constructors provided that these constructors have different signatures. A class that does not have a constructor explicitly defined has a default parameterless constructor.

Having said these about a constructor, a few other things are worth to be noted by a constructor.

i. In Java, a constructor has the same name as the name of its class.

For example, in the given class <em>myClass</em>, the constructor(s) should also have the name <em>myClass</em>.

ii. A constructor does not have a return value. It is therefore wrong to write a constructor like this:

<em>public void myClass(){...}</em>

This makes option a incorrect.

iii. When a constructor with parameters is defined, the default parameterless constructor is overridden. This might break the code if some other parts  of the program depend on this constructor. So it is advisable to always explicitly write the default parameterless constructor.

This makes option d a correct option.

Other options b and c may also be correct but there is no additional information in the question to help establish or justify that.

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Signe wants to improve the security of the small business where she serves as a security manager. She determines that the busine
jek_recluse [69]

Answer:Obscurity

Explanation: Security through the obscurity is the mechanism that is used for the security purpose in an operating system by inducing the confidentiality in the internal parts of the operating system.

The functioning of the security through obscurity(STO) works by hiding the  flaws and errors related to security  of the operating system.Thus , Signe is willing to use obscurity system.

 

6 0
4 years ago
cout &lt;&lt; "Part 1" &lt;&lt; endl; // Part 1 // Enter the statement to print the numbers in index 4 and index 9 // put a spac
Margarita [4]

Answer and Explanation:

#include <iostream>

using namespace std;

int printEven(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2==0)

{

count++;

cout<<array[i]<<" ";

}

}

return count;

}

void printAll(int array[],int n)

{

for(int i=0;i<n;i++)

{

cout<<array[i]<<" ";

}

}

int computeTotalOdds(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2!=0)

{

count++;

 

}

}

return count;

}

int main()

{

int array1[20] = {3, 18, 1, 25, 4, 7, 30, 9, 80, 16, 17};

int numElements = 11;

cout << "Part 1" << endl;

cout<<array1[4]<<" "<<array1[9];

cout << endl;

cout<<array1[0]<<" "<<array1[8];

cout << endl;

array1[2]=12;

cout << "\nPart 2" << endl;

printAll(array1,numElements);

 

cout << "\nPart 3" << endl;

int evens;

evens=printEven(array1,numElements);

 

 

 

 

// This will print the number of evens in the array.

cout << endl << evens;

 

cout << "\nPart 4" << endl;

 

int total;

 

total=computeTotalOdds(array1,numElements);

cout << endl << total;

 

return 0;

}

3 0
3 years ago
Write an algorithm to sum to values
Elis [28]

Answer:

There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:

Let a,b be two numbers.

c=a+b;

print(c);

But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:

Let a be the variable where the input numbers are stored.

while(f==1)

{

printf(“Enter number”);

scanf(“Take number into the variable a”);

sum=sum+a;

printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);

scanf(“Take the input into the variable f”);

}

print(Sum)

Explanation:

hi there answer is given mar me as brainliest

5 0
3 years ago
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Vanyuwa [196]
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Fed [463]

Answer: idek what that is but okay ;v;

7 0
3 years ago
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