Answer:
The average value of
over the interval
is
.
Step-by-step explanation:
Let suppose that function
is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of
over the interval
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)



The average value of
over the interval
is
.
Answer:
3x^2 (5x^3 + 4x^2 - 8x - 1)
Step-by-step explanation:
The given expression is 15x^5 + 12x^4-24x^3-3x^2
Here we have to find the GCF of all the above terms.
The GCF is 3x^2, let's take out 3x^2 and write the remaining terms in the parenthesis.
15x^5 + 12x^4-24x^3-3x^2
=3x^2 (5x^3 + 4x^2 - 8x - 1)
Therefore, the factors are 3x^2 and (5x^3 + 4x^2 -8x -1).
15x^5 + 12x^4-24x^3-3x^2 = 3x^2 (5x^3 + 4x^2 -8x -1)
Thank you.
Question #1
Part A:
The y-intercept can be found when x = 0. If you look at your table, when x = 0, y = 5.
So the y-intercept is 5.Part B:
The slope is 22.Part C:
y = mx + b
y = 22x + 5
We are given 225 as the range, or in place of y.
225 = 22x + 5
220 = 22x
x = 10
The domain is 10.Question #2
Part A:
(2,255)
(5,480)
Standard form is Ax + By = C

Let's plug this into this form first:

Now, let's make it into Standard Form.

What, which is in the box, is your final answer. :)
Part B:
Function notation simply means replacing y with f(x).
We had y = 85x + 55
So your answer is:

Part C:
Using the final answer which we got in Part A, we would know that the y-intercept is (0,55) and the x-intercept is (-55/85, 0). We would plot these 2 points, and then draw a line between them. :)
Answer:
i believe its b
Step-by-step explanation: