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mylen [45]
2 years ago
5

The equation for the cost in dollars of producing computer chip is y = .000015x^2 - .03x +35. Where X is the number of chips pro

duced. Find the number of chips that minimizes the cost. What is the cost for that number of chips?
Mathematics
1 answer:
lilavasa [31]2 years ago
5 0

Answer:

The equation for the cost in dollars of producing computer chips

The equation for the cost in dollars of producing computer chips is C = 0.000015x^2 - 0.03x + 35, where x is the number of chips produce. Find the number of chips that minimizes the cost.

Step-by-step explanation:

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A store wants to print flyers to a advertise its grand opening.A printer will charge $50 and 0.05 per flyer.If the store has a b
Kamila [148]

So it can be

x=number of flyers

50+0.05x=100

0.05x=50

x=1000 flyers


Hope this helps

7 0
3 years ago
The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
Xelga [282]

Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20 (2)

By Fundamental Theorems of Calculus we expand both expressions:

\frac{F(3)-F(-2)}{3-(-2)} = -6

F(3) - F(-2) = -30 (1b)

\frac{F(5)-F(3)}{5-3} = 20

F(5) - F(3) = 40 (2b)

We obtain the average value of f over the interval [-2, 5] by algebraic handling:

F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)

F(5) - F(-2) = 10

\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}

\bar f = \frac{10}{7}

The average value of f over the interval [-2,5] is \frac{10}{7}.

4 0
2 years ago
Factor completely 15x^5 + 12x^4-24x^3-3x^2
diamong [38]

Answer:

3x^2 (5x^3 + 4x^2 - 8x - 1)

Step-by-step explanation:

The given expression is 15x^5 + 12x^4-24x^3-3x^2

Here we have to find the GCF of all the above terms.

The GCF is 3x^2, let's take out 3x^2 and write the remaining terms in the parenthesis.

15x^5 + 12x^4-24x^3-3x^2

=3x^2 (5x^3 + 4x^2 - 8x - 1)

Therefore, the factors are 3x^2 and (5x^3 + 4x^2 -8x -1).

15x^5 + 12x^4-24x^3-3x^2 = 3x^2 (5x^3 + 4x^2 -8x -1)

Thank you.

7 0
3 years ago
PLEASE HELP!!!!!
Zielflug [23.3K]
Question #1

Part A:
The y-intercept can be found when x = 0. If you look at your table, when x = 0, y = 5. So the y-intercept is 5.

Part B:
\sf Slope = \frac{27-5}{1-0} = \frac{22}{1} = \boxed{22}
The slope is 22.

Part C:
y = mx + b
y = 22x + 5

We are given 225 as the range, or in place of y.
225 = 22x + 5
220 = 22x
x = 10

The domain is 10.



Question #2

Part A:

(2,255)
(5,480)

Standard form is Ax + By = C

\sf Slope = \frac{y_2-y_1}{x_2-x_1} = \frac{480-225}{5-2} = \frac{255}{3} = \boxed{85}

Let's plug this into this form first:
y - y_1 = m(x-x_1)\\\\y -225 = 85(x-2)\\\\y - 225 = 85x - 170\\\\y = 85x + 55

Now, let's make it into Standard Form.
y = 85x + 55\\\\y - 85x + 55\\\\ -85x + y = 55\\\\ -1(-85x +y) = -1(55)\\\\\boxed{85x - y = -55}
What, which is in the box, is your final answer. :)

Part B:
Function notation simply means replacing y with f(x).
We had y = 85x + 55
So your answer is:
\boxed{f(x) = 85x + 55}

Part C:
Using the final answer which we got in Part A, we would know that the y-intercept is (0,55) and the x-intercept is (-55/85, 0). We would plot these 2 points, and then draw a line between them. :)
5 0
3 years ago
What is the answer is it A. or B. or C. ?
nekit [7.7K]

Answer:

i believe its b

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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