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2 years ago

Kerri has a germen shepherd that has a mass of 30,000 grams. how many kilograms is 30,000 grams

Mathematics

1 answer:

wolverine [178]2 years ago

8 0

Answer: 30 kilograms

explanation: Each 1000 grams converts to 1 kilogram

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50 POINTS

NeX [460]

Answer:

o I = 4 cm, w = 9 cm, h = 3 cm

Step-by-step explanation:

The volume is given by V = l*w*h

w = 6 cm, I = 4,cm, h = 4 cm V= 6*4*4 = 96

o w = 7 cm, h = 3 cm, I = 5 cm V = 7*3*5 =105

o I = 4 cm, w = 9 cm, h = 3 cm V = 4*9*3 =108

o h = 5 cm, w = 6 cm, I = 3 cm V = 5*6*3 =90

The largest volume is

o I = 4 cm, w = 9 cm, h = 3 cm V = 4*9*3 =108

8 0

2 years ago

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Can someone pls i will give brainliest :)

satela [25.4K]

Answer:

149 degrees

Step-by-step explanation:

Higher value:

114

Lower value:

-35

Finding the difference:

114 - (-35)

114 + 35

149

6 0

2 years ago

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Write the number 1.665 × 10-1 in standard form.

saveliy_v [14]

0.1665 is standard form

5 0

2 years ago

The volume of a cone of radius r and height h is given by V=πr²h³. If the radius and the height both increase at a constant rate

Aloiza [94]

Answer:

The volume of cone is increasing at a rate 1808.64 cubic cm per second.

Step-by-step explanation:

We are given the following in the question:

$\dfrac{dr}{dt} = 12\text{ cm per sec}\\\\\dfrac{dh}{dt} = 12\text{ cm per sec}$

Volume of cone =

$V = \dfrac{1}{3}\pi r^2 h$

where r is the radius and h is the height of the cone.

Instant height = 9 cm

Instant radius = 6 cm

Rate of change of volume =

$\dfrac{dV}{dt} = \dfrac{d}{dt}(\dfrac{1}{3}\pi r^2 h)\\\\\dfrac{dV}{dt} = \dfrac{\pi}{3}(2r\dfrac{dr}{dt}h + r^2\dfrac{dh}{dt})$

Putting values, we get,

$\dfrac{dV}{dt} = \dfrac{\pi}{3}(2(6)(12)(9) + (6)^2(12))\\\\\dfrac{dV}{dt} =1808.64\text{ cubic cm per second}$

Thus, the volume of cone is increasing at a rate 1808.64 cubic cm per second.

5 0

3 years ago

How to solve for 4(m - 2 ) = 24

tino4ka555 [31]

4(m - 2 ) = 24

Divide both sides by 4

m - 2 = 8

add 2 to both sides

m = 10

Hope this helps! ;)

3 0

3 years ago

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