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3 years ago

Someone please help me I’ll give out brainliest please dont answer if you don’t know

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

4 0

Answer=0.4
Explanation

FromTheMoon [43]3 years ago

4 0

Answer:

Step-by-step explanation:

Ok, so remember your order of operations here.

Also, Remember that what we do to one side, we must do to the other side.

We cant solve whats in the parentheses, so that wont come first. The next best thing is the multipication of 0.8 in front of it:

0.8x(2x-4)

1.6x-3.2

Now lets rewrite the equation as:

1.6x-3.2=16

Now lets simply solve the rest:

1.6x=19.2

All I did is add 3.2 to both sides so I could get 1.6x on its own.

What is left is just dividing 1.6x to get 1x:

1.6x/1.6=19.2/1.6

This gets us:

x=12

This is because we divided 1.6 from both sides so that 1.6x became just x.

Answer:

<u>12</u>

Hope this helps!

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While on a train trip, Marsha noticed that there were 35 people in her train car. After the next stop, there were only 21 people

const2013 [10]

Answer:

40%

Step-by-step explanation:

To find a percent, divide the part by the total and multiply by 100.

To find the part, subtract 21 from 35 to find the people who left.

35 - 21 = 14

(14/35)*100 = p

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Answer:

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3 years ago

Express the system as AX = B; then solve using matrix inverses

Wittaler [7]

Answer with explanation:

1. The given equations are

3x -5 y=2

-x+2 y= 0

⇒The matrix in the form of , AX=B, is

$A=\left[\begin{array}{cc}3&-5\\-1&2\end{array}\right] ,\\\\ X=\left[\begin{array}{c}x&y\end{array}\right],\\\\B=\left[\begin{array}{c}2&0\end{array}\right]$

$\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B$

Adj.A=Transpose of cofactor of Matrix A

$Adj.A=\left[\begin{array}{cc}2&1\\5&3\end{array}\right] ,\\\\ |A|=6-5\\\\|A|=1\\\\\left[\begin{array}{c}x&y\end{array}\right]=\left[\begin{array}{cc}2&5\\1&3\end{array}\right] \times \left[\begin{array}{c}2&0\end{array}\right]\\\\x=4, y=2$

The given equations are

x+y-z=2

x+z=7

2 x +y+z=13

⇒The matrix in the form of , AX=B, is

$A=\left[\begin{array}{ccc}1&1&-1\\1&0&1\\2&1&1\end{array}\right]\\\\ X=\left[\begin{array}{ccc}x\\y\\z\end{array}\right]\\\\B= \left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B\\\\a_{11}=-1,a_{12}=1,a_{13}=1,a_{21}=-2,a_{22}=3,a_{23}=1,a_{31}=1,a_{32}=-2,a_{33}=-1\\\\|A|=1\times(0-1)-1\times(1-2)-1\times(1-0)\\\\=-1+1-1\\\\|A|=-1\\\\Adj.A=\left[\begin{array}{ccc}-1&-2&1\\1&3&-2\\1&1&-1\end{array}\right]$

$\frac{Adj.A}{|A|}=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\\\\X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\times\left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\x=3,y=3,z=4$

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3 years ago

Simplify <br> 2x x y x 3

nikitadnepr [17]

Which is it
2x times y times 3 = 6xy
or,
2xxyx3= 6x^3y

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3 years ago