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3 years ago

14

I need help with 9 and 10

1 answer:

adell [148]3 years ago

7 0

#9) 180 - 116 = 64

(3x -13) + ( 2x +4 ) + 64 = 180

5x - 9 + 64 = 180

5x = 180 + 9 - 64

5x = 125

x = 25

#10) 3x - 13

= (3× 25) - 13 = 62

m< A = 62°

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4 years ago

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As it has been given that $x=4+5i$ , $y=2-9i$ .

We need to find the value of the following:

(i) $4x-y$ , substituting the value of 'x' and 'y' in the expression, we get:

$4(4+5i)-(2-9i)=4\times 4+4\times 5i-2+9i=16+20i-2+9i$

$=14+29i$

So, $4x-y=14+29i$

(ii) $-x+3y$ , substituting the value of 'x' and 'y' in the expression, we get:

$-(4+5i)+3(2-9i)=-4-5i+3\times 2-3 \times 9i=-4-5i+6-27i$

$=2-32i$

So, $-x+3y=2-32i$

(iii) $x \times y$ , we need to substitute the value of 'x' and 'y' in the expression, for this, we can use distributive property of multiplication that says,

$a(b+c)=a \times b+ a \times c$

Using the distributive property of multiplication:

$(4+5i)\times(2-9i)=4 \times 2-4 \times 9i+5i \times 2-5i \times 9i$

$=8-36i+10i-45i^2$

Now, we know that $i \times i=i^2=-1$

We get, $8-36i+10i-45 \times (-1)=8-26i+45$

$=8+45-26i=53-26i$

Therefore, $x \times y$ = $53-26i$ .

(iv) We have, $2x \times y$ , we need to substitute the value of 'x' and 'y' in the expression, we get:

$2(4+5i)\times (2-9i)$

Again, we can use distributive property of multiplication that says,

$a(b+c)=a \times b+ a \times c$

So,

$2(4+5i) \times (2-9i)=2\times 4+2 \times 5i\times(2-9i)$

$=8+10i \times(2-9i)=8\times 2-8 \times 9i+10i \times 2-10i \times 9i$

$=16-72i+20i-90i^2$

since, $i^2=-1$

we get,

$16-72i+20i-90 \times (-1)=16-52i+90$

$=106-52i$

Therefore,

$2x \times y=106-52i$

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4 years ago

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