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statuscvo [17]
2 years ago
12

10. What is the value of x in the solution to the system of equations?

Mathematics
1 answer:
RUDIKE [14]2 years ago
3 0

Solve for x in first equation:

x-2y=7

Add “2y” to both sides

x=2y+7

Put this in to second equation:

3(2y+7)+2y=21

Solve for y:

Distribute the 3 into the ()

6y+21+2y=21

Combine the like y terms

8y+21=21

Subtract 21 from both sides

8y=0

Divide by 8 on both sides

y=0

Put this into the first solved equation:

x=2(0)+7

Solve for x:

Multiple 2(0)

x=0+7

Add 0 and 7

x=7

So the value of x is positive 7.

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Step-by-step explanation:

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2 years ago
15 POINTS PLEASE HELP!
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
An economist uses the price of a gallon of milk as a measure of inflation. She finds that the average price is $3.82 per gallon
salantis [7]

Answer:

(a) The standard error of the mean in this experiment is $0.052.

(b) The probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c) The probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d) The likelihood that the sample mean is greater than $3.92 is 0.9726.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

n=40\\\mu=\$3.82\\\sigma=\$0.33

As <em>n</em> = 40 > 30, the distribution of sample mean is \bar X\sim N(3.82,\ 0.052^{2}).

(a)

The standard error is the standard deviation of the sampling distribution of sample mean.

Compute the standard deviation of the sampling distribution of sample mean as follows:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

    =\frac{0.33}{\sqrt{40}}\\\\=0.052178\\\\\approx 0.052

Thus, the standard error of the mean in this experiment is $0.052.

(b)

Compute the probability that the sample mean is between $3.78 and $3.86 as follows:

P(3.78

                               =P(-0.77

Thus, the probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c)

If the difference between the sample mean and the population mean is less than $0.01 then:

\bar X-\mu_{\bar x}

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

Thus, the probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d)

Compute the probability that the sample mean is greater than $3.92 as follows:

P(\bar X>3.92)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{3.92-3.82}{0.052})

                    =P(Z

Thus, the likelihood that the sample mean is greater than $3.92 is 0.9726.

3 0
3 years ago
PLEASE HELP ME ON THIS
ra1l [238]

Answer:

<h2>B</h2>

Step-by-step explanation:

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7 0
2 years ago
Use the formula C(n, x)pxqn − x to determine the probability of the given event. (Round your answer to four decimal places.) The
miskamm [114]

Answer: 0.1334

Step-by-step explanation:

Given

There are seven trails with a probability of success is  p=\frac{1}{4}

\therefore q=1-p\\q=1-\frac{1}{4}\\q=\frac{3}{4}

Using the binomial distribution, the Probability of exactly no success i.e. x=0 is given by

\Rightarrow ^7C_0\cdot p^0 \cdot q^{7-0}\\\Rightarrow 1\times(\frac{1}{4})^0 \cdot (\frac{3}{4})^7\\\Rightarrow 1\times 1 \cdot (0.75)^7\\\Rightarrow 0.1334

7 0
2 years ago
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