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3 years ago

Find the selling price of a $15.25 pair of socks with a 18% discount. Round to the nearest cent when necessary.

1 answer:

4 0

I believe the answer would be $12.50. multiply the original price and the discount percentage and divide that by 100. once you get the amount saved, which in this case would be $2.75, subtract that from the original price.

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ANSWER THE QUESTION FOR BRAINLIESTANSWER THE QUESTION FOR BRAINLIEST

rewona [7]

Answer:

A) Ed

Explanation: How i got it was by first looking at what Eric’s weight loss program, I then guessed he lost about the same amount of weight each week (1.5), i then did that times 4 since that’s how many weeks were recorded on the chart which gave me 6. I then looked at the chart again and saw that Ed first started with the weight 205 and by week 4 his weight was 197, I then did 205-197 which equals 8, I then decided that Ed lost more weight.

3 0

3 years ago

Read 2 more answers

How many liters of water vapor can be made from 34.0 grams of oxygen gas and excess amount of hydrogen gas at STP?

AVprozaik [17]

8.2 L is the correct answer

7 0

3 years ago

Solve for x -5(x-4)=-30

Naily [24]

Answer:

-5x + 20 = -30

-5x = 10

x = -2

7 0

3 years ago

Please answer this question

Vladimir [108]

Answer:

a = 3/2
b = -1/2

Step-by-step explanation:

$\dfrac{\sqrt{5}-1}{\sqrt{5}+1}=\dfrac{(\sqrt{5}-1)(\sqrt{5}-1)}{(\sqrt{5}+1)(\sqrt{5}-1)}\\\\=\dfrac{5-2\sqrt{5}+1}{5-1}=\dfrac{6-2\sqrt{5}}{4}\\\\=\dfrac{3}{2}-\dfrac{1}{2}\sqrt{5}$

Comparing this to the form a+b√5, we see that ...

a = 3/2

b = -1/2

8 0

3 years ago

Suppose the number of hits a webpage receives follows a Poisson distribution. The average number of hits per minute is 2.4. What

REY [17]

Answer:

The probability that the page will get at least one hit during any given minute is 0.9093.

Step-by-step explanation:

Let X = number of hits a web page receives per minute.

The random variable X follows a Poisson distribution with parameter,

λ = 2.4.

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

Compute the probability that the page will get at least one hit during any given minute as follows:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-\frac{e^{-2.4}(2.4)^{0}}{0!}\\=1-\frac{0.09072\times1}{1} \\=1-0.09072\\=0.90928\\\approx0.9093$

Thus, the probability that the page will get at least one hit during any given minute is 0.9093.

6 0

3 years ago