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AleksAgata [21]
3 years ago
13

Please HELP MEEEEEEEEEEEEEEEEEE

Mathematics
1 answer:
slavikrds [6]3 years ago
8 0

Answer:

Choice c.

Step-by-step explanation:

The domain of a rational function is found where the denominator of the fraction is equal to 0.  These are the values that are NOT allowed.  We have to factor the denominator completely to find these values that make the denominator equal 0.  In other words, our denominator right now is:

x(x^2-16)

we set each factor equal to 0:

x = 0 or

x^2-16=0

The left side of that quadratic is the difference of perfect squares, so it factors into the 2 binomials:

(x + 4)(x - 4)

Setting each of those equal to 0 we can solve for the values of x that are not allowed:

If x + 4 = 0, then

x ≠ 4.

If x - 4 = 0, then

x ≠ -4

So the domain for this rational function is:

{x I x ≠ ±4, x ≠ 0},

which is c.

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Answer:


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lutik1710 [3]

Answer:

What is the question?

Step-by-step explanation:

7 0
3 years ago
P is inversely proportional to the cube of (q-2) p=6 when q=3 find the value of p when q is 5
sveticcg [70]
\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
\\
&&y=\cfrac{{{  k}}}{x}
\end{array}\\\\
-----------------------------\\\\
\textit{p is inversely proportional to the cube of (q-2)}\implies p=\cfrac{k}{(q-2)^3}
\\\\\\
now \quad 
\begin{cases}
p=6\\
q=3
\end{cases}\implies 6=\cfrac{k}{(3-2)^3}

solve for "k", to find k or the "constant of variation"

then plug k's value back to \bf p=\cfrac{k}{(q-2)^3}

now.... what is "p" when q = 5?  well, just set "q" to 5 on the right-hand-side, and simplify, to see what "p" is
4 0
3 years ago
Square root of 2025 by prime factorisation method​<br>Please explain step by step
Mice21 [21]

Answer:

45

Step-by-step explanation:2025....use the smallest prime number to divide the number 2025 till you get to a point were it can't be divided again . Group each prime number with a partner of its value like this :

5×5×3×3×3×3........ then use bracket to separate them like this (5×5)(3×3)(3×3)........ then take a number from each 5×3×3 then multiply to get 45

4 0
3 years ago
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