Answer:
Step-by-step explanation:
we know that distance d from the focus to P should be the same to the distance from P to the directrix
(x-h)^2=4p(y-k)
we need to find the y coordinate,
x is the same from focus, 3
y=(3, (4+2)/2)=(3,3)
we find p now by subtracting the y from the focus from the y that we just found
p=4-3=1
again (x-h)^2=4p(y-k), p=1
(x-3)^2=4(1)(y-3)
(x-3)^2=4(y-3), (x-3)^2=4y-12
simplify
4y=(x-3)^2+12
y=((x-3)^2)/4 + 3
The equation of the line is y = 0.8x - 1.4 if the slope of the line is 0.8 and line passes through coordinates (-2,-3)
<h3>What is a straight line?</h3>
A straight line is a combination of endless points joined on both sides of the point.
The slope 'm' of any straight line is given by:

The slope m = 0.8
The line passing through coordinates (-2,-3)
y = mx + c
y = 0.8x + c
Plug the point in the equation.
-3 = 0.8(-2) + c
c = -1.4
y = 0.8x - 1.4
Thus, the equation of the line is y = 0.8x - 1.4 if the slope of the line is 0.8 and line passes through coordinates (-2,-3)
Learn more about the straight line here:
brainly.com/question/3493733
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2x^2+9x-6 i found this by subtracting 3x^2+7x from the other equation