Answer:
Cost of a single Mucho beef burrito: 
Cost of a double Mucho beef burrito: 
Step-by-step explanation:
<h3>
The exercise is: "The Little Mexican restaurant sells only two kinds of beef burritos: Mucho beef and Mucho Mucho beef. Last week in the restaurant sold 16 orders of the single Mucho variety and 22 orders of the double Mucho. If the restaurant sold $231 Worth of beef burritos last week and the single neutral kind cost $1 Less than the double Mucho, how much did each type of burrito cost?"</h3>
Let be "x" the the cost in dollars of a single Mucho beef burrito and "y" the cost in dollars of a double Mucho burrito.
Set a system of equations:
To solve this system you can apply the Substitution Method:
1. Substitute the second equation into the first equation and solve for "y":
2. Substitute the value of "y" into the second equation and evaluate in order to find the value of "x":
Answer:
Step-by-step explanation:
hg(x) means you multiply h(x) times g(x) and then we will set it equal to 
.
hg(x) = 
which simplifies to
. Now set that equal to :
and get everything on the same side and factor:
. Factor by grouping:
and factor out what's common in each set of ( ):
which factors out to
. But 
factors somoe to:
(x + 1)(x - 1)(x - 1) = 0 So the solutions for this are
x = -1, 1
Answer: ∆V for r = 10.1 to 10ft
∆V = 40πft^3 = 125.7ft^3
Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________
[v(r)=4/3Ï€r^3].
Step-by-step explanation:
Volume of a sphere is given by;
V = 4/3πr^3
Where r is the radius.
Change in Volume with respect to change in radius of a sphere is given by;
dV/dr = 4πr^2
V'(r) = 4πr^2
V'(10) = 400π
V'(10.1) - V'(10) ~= 0.1(400π) = 40π
Therefore change in Volume from r = 10 to 10.1 is
= 40πft^3
Of by direct substitution
∆V = 4/3π(R^3 - r^3)
Where R = 10.1ft and r = 10ft
∆V = 4/3π(10.1^3 - 10^3)
∆V = 40.4π ~= 40πft^3
And for R = 30ft to r = 10.1ft
∆V = 4/3π(30^3 - 10.1^3)
∆V = 34626.3πft^3
The answer is f(x) = (x/4) - 3
4/4=1-3=-2
