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zheka24 [161]
3 years ago
13

5) 5n2 + 10n + 20how do you solve this? ​

Mathematics
2 answers:
lakkis [162]3 years ago
8 0

use a calc

Step-by-step explanation:

Bas_tet [7]3 years ago
7 0

Answer: 5(n2+2n+4)

Step-by-step explanation: hope this help

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there are 28 tables in the cafeteria.each table has 12 students sitting at it.fourth graders sit at 13 of the yables.fifth grade
Darya [45]
Hope this helps!

28 - 13 = 15
15 x 12 = 180 Fifth graders
6 0
3 years ago
Which space figure has six faces that are all regular quadrilaterals
nadya68 [22]
It would be a cube or a square prism. 
6 0
4 years ago
Tan(-212°)=____.<br><br> 1. -cot 32°<br> 2. tan 32°<br> 3. cot 32°<br> 4. -tan 32°
Marrrta [24]

Answer:

4. -\tan 32°

Step-by-step explanation:

Given:

The tangent of the angle is given as:

\tan (-212\°)

Since the angle is negative, it means that it is measured in the clockwise direction as angles measured in clockwise direction are negative and that measured in counter clockwise directions are positive.

-212° when measured from counter clockwise direction will be equal to:

-212\°(Clockwise)=360-212=148\°(CCW)

Therefore, \tan (-212\°) = \tan (148\°)

Now, we have the identity for tan as:

\tan(\pi-\theta)=-\tan \theta

Here, \theta=148\°

Therefore,

-\tan (148\°)=\tan(180-148)\\-\tan(148\°)=\tan(32\°)\\\textrm{Multiplying both sides by -1, we get:}\\-1(-\tan(148\°)=-1\times \tan(32\°)\\\\\tan(148\°)=-\tan(32\°)

Hence, \tan (-212\°) = \tan (148\°) = -\tan 32°

5 0
3 years ago
#40 please! Thank you.
lisov135 [29]
Well he and the cart together weigh: 210+95=305.
The weight left for boxes is: 4,000-305=3,695.
Total weight of boxes is: 50·275=13,750.
Divide the weight of boxes by how much is left for the elevator: 13,750/3,695=3.72
Since 3.72 is more than 3 he would have to make 4 trips to safely do so :)
5 0
3 years ago
Which of the following sets contain all roots of the polynomial
Zarrin [17]

All these given roots are contained in option C.

The given equation is :

9x^{3}+9x^{2}-4x-4=0

9x^{2}(x+1)-4(x+1)=0

(9x^{2}-4)(x+1)=0

9x^{2}-4=0,x+1=0

x^{2}=\frac{4}{9},x=-1

x=\frac{2}{3},x=-1

Roots = -1,\frac{-2}{3} ,\frac{2}{3}

Hence these lie in between (\frac{-3}{2} ,\frac{3}{2})


8 0
3 years ago
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