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dimulka [17.4K]

3 years ago

15

the sum of three numbers is 62 the second number is equal to the first number diminished by for the third number is four times t

he first

1 answer:

vladimir1956 [14]3 years ago

8 0

Answer:

11, 7, 44

Step-by-step explanation:

a+b+c = 62

a-4 = b

c = 4×a

I think you meant "diminished by four", right ?

=>

a + a-4 + 4×a = 62

6×a - 4 = 62

6×a = 66

a = 11

=>

b = 11 - 4 = 7

c = 4×11 = 44

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Answer:

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3 years ago

Find x in this 45°-45°-90° triangle.<br><br><br><br> x =

Zielflug [23.3K]

Use a^2 + b^2 = c^2

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3 years ago

The circular mirror hanging on Belle's wall has a diameter of 18 inches. What is the

just olya [345]

Answer:

56.52 inches

Step-by-step explanation:

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c=3.14*18 <em>Multiply</em>

c=56.52

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3 years ago

Abygail is building a dollhouse. She has boards that are two different lengths. One long board is 10 inches longer than the tota

nikitadnepr [17]

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Step-by-step explanation:

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3 years ago

The equation 7^2=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A

jeyben [28]

Answer:

The period of Y increases by a factor of $k^ {3/2}$ with respect to the period of X

Step-by-step explanation:

The equation $T ^ 2 = a ^ 3$ shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?

For the planet Y:

$T_y ^ 2 = a_y ^ 3$

For planet X:

$T_x ^ 2 = a_x ^ 3$

To know the factor of aumeto we compared $T_x$ with $T_y$

We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:

$a_y ^ 3 = (a_xk) ^ 3$

So

$\frac{T_y ^ 2}{T_x ^ 2}=\frac{a_y ^ 3}{a_x^ 3}\\\\\frac{T_y ^ 2}{T_x ^ 2}=\frac{(a_xk)^3}{a_x ^ 3}\\\\\frac{T_y^ 2}{T_x^ 2}=\frac{k ^ {3}a_{x}^ 3}{a_{x}^ 3}\\\\\frac{T_{y}^ 2}{T_{x}^ 2}=k ^ 3\\\\T_{y}^ 2 = T_{x}^{2}k^{3}\\\\T_{y} =k^{\frac{3}{2}}T_x$

Then, the period of Y increases by a factor of $k^ {3/2}$ with respect to the period of X

4 0

4 years ago