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3 years ago

Need helpppppppppp! Show work plz

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

5 0

Answer:

9/169

Step-by-step explanation:

JQK of 4 suits = 12 cards

12/52x12/52=

3/13x3/13=

9/169

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-5x-4y=-7 on a graph

Flauer [41]

Answer:

Graph is attached below.

Step-by-step explanation:

If you want to solve for the variable x,

x = −4 / 5y + 7 / 5

3 0

3 years ago

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

tigry1 [53]

Answer:

$P(A) = \frac{30}{100}$

$P(B) = \frac{77}{100}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

Step-by-step explanation:

Given

See attachment for proper format of table

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

$Yes = 22$ and $No = 8$

So, we have:

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

So, we have:

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

8 0

3 years ago

Tori went to the eye doctor. He dilated her pupils to twice their normal size during the exam. If her pupils were 2 mm oeiginall

jok3333 [9.3K]

4 pupils bc 2*2=4..................................................................................................................................................................................................................................................................

6 0

3 years ago

Read 2 more answers

6) What happens to the diameter of the field of view as the magnification increases?

Diano4ka-milaya [45]

Answer:

There is an inverse relationship between the total magnification and the diameter of the field of view – i.e., as magnifications increases the diameter of the field decreases in proportion, so the diameter of field of view at different magnification can be calculated mathematically, using the formula.

Step-by-step explanation:

4 0

3 years ago

Can someone hepl me solve this it is importaint thank you so much ?<br><br> 4/7x5/3x3/4=?

erastovalidia [21]

Answer:

5/7 is the answers for the question

3 0

2 years ago