1 mol CuSO₄·5H₂O ----------- 5 mol H₂O
0,25 mol CuSO₄·5H₂O ---- Xmol H₂O
X = 5×0,25 = 1,25 mol H₂O
Answer:
molarity = no. of moles of solute / 1 liter .
* one moles of sodium hydroxide = 40 gm of sodium hydroxide.
so we can said ; if want prepare 1 molar NaOH solution then we need 40 gm NaOH dissolve in one liter of water so it became one 1 molar NaOH solution
Explanation:
Hey there!:
Molar mass NaCl = 58.44 g/mol
Number of moles:
n = mass of solute / molar mass
n = 15.6 / 58.44
n = <span>0.2669 moles of NaCl
hope this helps!</span>
Answer:
41.56 g
Explanation:
Given data:
Mass of NH₄Cl = 15.50 g
Actual yield of AgCl = 35.50 g
Theoretical yield of AgCl = ?
Solution:
Chemical equation:
NH₄Cl + AgNO₃ → AgCl + NH₄NO₃
Number of moles of NH₄Cl:
Number of moles = mass/ molar mass
Number of moles = 15.50 g/ 53.491 g/mol
Number of moles = 0.29 mol
Now we will compare the moles of NH₄Cl with AgCl .
NH₄Cl : AgCl
1 : 1
0.29 : 0.29
Theoretical yield of AgCl:
Mass = number of moles × molar mass
Mass = 0.29 mol ×143.32 g/mol
Mass = 41.56 g
