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Serga [27]
3 years ago
15

How many moles of compound are there in the following?

Chemistry
1 answer:
slavikrds [6]3 years ago
8 0

a) (NH4)2SO4 --- 1 mole of it contains 2 moles of N, 8 moles of H, 1 mole of S, and 4 moles of O.

MM = (2 moles N x 14.0 g/mole) + (8 moles H x 1.01 g/mole) + (1 mole S x 32.1 g/mole) + (4 moles O x 16.0 g/mole) = 132 g/mole.

6.60 g (NH4)2SO4 x (1 mole (NH4)2SO4 / 132 g (NH4)2SO4) = 0.0500 moles (NH4)2SO4

b) The molar mass for Ca(OH)2 = 74.0 g/mole, calculated like (NH4)2SO4 above.

4.5 kg Ca(OH)2 x (1000 g / 1 kg) x (1 mole Ca(OH)2 / 74.0 g Ca(OH)2) = 60.8 moles Ca(OH)2

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The ionization energies for removing successive electrons from sodium are 496 kJ/mol, 4562 kJ/mol,
ddd [48]

Answer:

D

Explanation:

The high jump of ionization energy indicates that we are trying to remove electron from noble gas configuration state.

The ionization energy data specifies that the Elements are from group 1 at period 3 or greater.

Removing the first electron require 496 kJ and the second ionization energy jump significantly due to the removal of electron from the noble gas configuration which is logical because electron try to maintain the especially stable state.

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The fourth one.

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About 97.5% of Earth’s water is
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6 0
3 years ago
5.) The density of a black hole is estimated to be as high as 6 x 1015 kg/m?. Using this density, what would be the
adell [148]
<h3>Answer:</h3>

1.6 × 10^2 teragrams

<h3>Explanation:</h3>
  • Density is the ratio of the mass of object to its volume.
  • It is calculated by;

Density = Mass ÷ Volume

we are given;

Density of a black hole = 6×10^15 kg/m³

Volume of the black hole = 2.5 in or 6.35 cm in volume

But; 1 g/cm³ = 1000 kg/m³

Therefore; 6×10^15 kg/m³ =6×10^12 g/cm³

We are required to get mass;

Volume = 4/3(πR³)

Assuming the radius is 2.5 inches or 6.35 cm

             = 4/3 × 3.14 × 6.35 ³

             = 26.585 cm³

But; Mass = Density × volume

                = 6×10^12 g/cm³ × 26.585 cm³

                = 1.6 × 10^14 g

but; 1 telegram = 1 teragram = 10^12 g

Therefore; 1.6 × 10^14 g ÷10^12 g

                 =  1.6 × 10^2 teragrams

Therefore, the mass of the black hole is 1.6 × 10^2 teragrams

4 0
3 years ago
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