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Norma-Jean [14]
3 years ago
15

How many moles of NaCl are equivalent to 15.6g NaCl

Chemistry
2 answers:
aev [14]3 years ago
7 0
Hey there!:

Molar mass NaCl = 58.44 g/mol

Number of moles:

n = mass of solute / molar mass

n = 15.6 / 58.44

n = <span>0.2669 moles of NaCl

hope this helps!</span>
elena-s [515]3 years ago
5 0

Explanation:

It is known that number of moles equal mass divided by molar mass of compound.

Mathematically,     Number of moles = \frac{mass}{molar mass}

Since, it is given that mass is 15.6 g and molar mass of NaCl is 58.44 g/mol.

Therefore, calculate the number of moles of NaCl as follows.

           Number of moles = \frac{mass}{molar mass}    

                                         = \frac{15.6 g}{58.44 g/mol}    

                                         = 0.266 mol

Thus, we can conclude that there are 0.266 moles of NaCl are equivalent to 15.6g NaCl.

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Balancing Chemical Equation<br> Na+Br2=NaBr
solniwko [45]

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2Na + Br2 = 2NaBr

Explanation:

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Na+ Br2 = NaBr

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3 years ago
Which water usage uses the least amount of water in a year in the United States
statuscvo [17]

Answer: a

Explanation:

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4 0
2 years ago
What is the limiting reagent when a 2.00 g sample of ammonia is mixed with 4.00 g of oxygen?​
UNO [17]

Answer:

Ammonia is limiting reactant

Amount of oxygen left  = 0.035 mol

Explanation:

Masa of ammonia = 2.00 g

Mass of oxygen = 4.00 g

Which is limiting reactant = ?

Balance chemical equation:

4NH₃ + 3O₂     →     2N₂ + 6H₂O

Number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 2.00 g/ 17 g/mol

Number of moles = 0.12 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

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Number of moles = 0.125 mol

Now we will compare the moles of ammonia and oxygen with water and nitrogen.

                      NH₃          :            N₂

                        4             :             2

                      0.12           :           2/4×0.12 = 0.06

                      NH₃         :            H₂O

                        4            :             6

                        0.12       :           6/4×0.12 = 0.18

                       

                       O₂            :            N₂

                        3             :             2

                      0.125        :           2/3×0.125 = 0.08

                        O₂           :            H₂O

                        3              :             6

                        0.125       :           6/3×0.125 = 0.25

The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.

Amount of oxygen left:

                        NH₃          :             O₂

                           4            :              3

                           0.12       :          3/4×0.12= 0.09

Amount of oxygen react = 0.09 mol

Amount of oxygen left  = 0.125 - 0.09 = 0.035 mol

3 0
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