i. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the
Answer: 271
Step-by-step explanation:
Answer:
unlikely
Step-by-step explanation:
thats alot of people
Change x+y=5 to y=5-x
x+5-x=-3
0=-8
The answer is no solution. :)
Answer:
x^2 - 2x - 12 with remainder 12
Step-by-step explanation:
Synthetic division is the fastest way in which to carry out this division.
The divisor (x - 1) from long division corresponds to the divisor 1 in synthetic division. Setting up synthetic division, we get:
1 / 1 -3 -10 24
1 -2 -12
--------------------------------
1 -2 -12 12
The first three digits {1, -2, -12} are the coefficients of the quotient, and 12 represents the remainder:
The quotient is 1x^2 - 2x - 12 and the remainder is 12.
