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Kryger [21]
3 years ago
13

If f(x)=x2+3x+5 what is f(3+h)

Mathematics
1 answer:
artcher [175]3 years ago
5 0
Here is your perfect answer

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Can you Help me out plz!!
Klio2033 [76]

Answer:

14)

21√2

15)

Leg: 7√3

Hypotenuse: 14

Step-by-step explanation:

The hypotenuse is √2 as long as each leg. That means the leg is 42/√2. Simplified to make 21√2.

The hypotenuse is always twice as long as the shortest leg on a 30-60-90 triangle. The longer leg is √3 as long as the shortest side.

4 0
3 years ago
1. In the picture below, if major arc BC is 258
WINSTONCH [101]

The answer is attached.

4 0
3 years ago
Suppose that lithium calculator battery with a charge of 3 volts, actually has a voltage with uniform distribution between 2.93
Dmitrij [34]

Answer:

b. E(X) = 3.015, STDEV(X)= 0.049, P (X ≤ 2.98) = 0.2941

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean of the uniform probability distribution is:

M = \frac{a + b}{2}

The standard deviation of the uniform distribution is:

S = \sqrt{\frac{(b-a)^{2}}{12}}

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

Uniform distribution between 2.93 and 3.1 volts

This means that a = 2.93, b = 3.1. So

Mean:

M = \frac{2.93 + 3.1}{2} = 3.015

Standard deviation:

S = \sqrt{\frac{(3.1 - 2.93)^{2}}{12}} = 0.049

What is the probability that a battery has a voltage less than 2.98?

P(X \leq 2.98) = \frac{2.98 - 2.93}{3.1 - 2.93} = 0.2941

So the correct answer is:

b. E(X) = 3.015, STDEV(X)= 0.049, P (X ≤ 2.98) = 0.2941

6 0
3 years ago
Find two z values, one positive and one negative, that are equidistant from the mean so that the areas in the two tails add to t
levacccp [35]
I think it would be the answer is b.
3 0
3 years ago
Help with Algebra! Completing the square!
Juli2301 [7.4K]
B. First off , standard form of a 2nd degree equation is Ax^2 + Bx + C. So look at the coefficient of Ax^2 which is -2.
If positive, the parabola opens up and has a minimum.
If negative, the parabola opens down and has a maximum.

A. To find the vertex (in this case maximum),
Graph the equation -OR—
make a table. — OR—
Find the zeroes and find the middle x-value
-2x^2 - 4x + 6
-2(x^2 +2x - 3 = 0
-2 (x - 1) ( x + 3)=0
x - 1 = 0. x + 3 = 0
x = 1. x = -3. So halfway would be at (-1, __).
Sub in -1 into original equation -2x^2 -4x + 6 … -2(-1)^2 -4(-1) + 6 = -2 +4 +6 = 8
So the vertex is (-1,8)


7 0
3 years ago
Read 2 more answers
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