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AysviL [449]
2 years ago
10

Someone help me asap

Mathematics
1 answer:
Marianna [84]2 years ago
7 0
30 + 70 + D = 180
100 + D = 180
D = 80°
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Hey need some help, pretty desperate so please help thank you <3
r-ruslan [8.4K]

Answer:

Hello!

answer x = 46

z = 24

y = 14

6 0
2 years ago
Please help me with this
Vinvika [58]

Put one point at -10,6 and another at 6,-10

6 0
3 years ago
If Gabby wants to buy a t-shirt for $35.99 but she has a discount for 10% off, how much is her final cost?
Leno4ka [110]

Answer:

It's $32.39.

Step-by-step explanation:

35.99 - 35.99*10% =

=35.99 - 35.99*0.1

=35.99 - 3.599

=32.391

32.391 is close to 32.39 so we will round it to that number.

The answer is $32.39.

6 0
3 years ago
Read 2 more answers
I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5
Gnesinka [82]
Given:
f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}

Using
\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}
we derive
\frac{d}{dx}4xcos^{-1}(2x+4)
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}

Similarly, using
\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}
we derive
\frac{d}{dx}(-\sqrt{3-3x^2})
=\frac{3x}{\sqrt{3-3x^2}}

Therefore, the derivative is
f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}
3 0
3 years ago
Read 2 more answers
A movie theater uses a cone-shaped container to serve popcorn. The cone has a height of 12 inches and a volume of 16 π in2. What
zimovet [89]

Volume can be defined as the <u><em>capacity of a given container or a certain object.</em></u>

The radius of the cone is 2 inches.

From the question, we are given the following parameters:

<em>The height of the cone = 12 inches</em>

<em>The volume of the cone =  16 π in³</em>

The formula to find the<u> radius of the cone </u>is given as:

√3V/πh

= √ 3 x 16π / π x 12

= 2 inches

Therefore, the radius of the cone is 2 inches.

To learn more, visit the link below:

brainly.com/question/25107622

6 0
2 years ago
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