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2 years ago

Can somebody please help me with this question and provide an explanation?

Mathematics

2 answers:

SSSSS [86.1K]2 years ago

7 0

Answer:

first of all the formula

y = mx+c

where m is slope and c is y-intercept.

now substitute the values-

y = 2x - 5

(for the slope here is 2 and the part where the line intercepts y axis is -5

therefore

y = 2x-5

mario62 [17]2 years ago

5 0

Answer:

I have a question for you how are not going to help others but want help yourself sounds lazy to me...

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Step by step pleasee -- algerbra 2<br><br><br>g(a) = 4a ; find g(2a)

Iteru [2.4K]

The value of f(2a) is 8a

<h3>What is a function?</h3>

A function can be defined as a rule or expression that shows the relationship between a dependent and independent variable.

From the information given, we have;

g(a) = 4a

Let's determine the value for f(2a)

a = 2a

Let's substitute the value of a as 2a in the function

g(a) = 4a

g(2a) = 4 ( 2a)

Multiply through

g(2a) = 8a

Thus, the value of f(2a) is 8a

Learn more about functions here:

brainly.com/question/2456547

#SPJ1

4 0

1 year ago

What is the slope of the line passing through the points (-1,-7) and (-9, -2) ?

Dominik [7]

The equation for slope is:
(y2 - y1) / (x2 - x1)

-2 -(-7) = 5
-9 -(-1) = -8

Slope of the line:

5/-8 or -5/8

7 0

2 years ago

Read 2 more answers

Please answer this question ASAP

Vilka [71]

Answer:

First, second, third, and fourth are functions

Step-by-step explanation:

Each input in the first, second, third, and fourth only have one output. In the fifth one 3.3 and 6.6 are seen twice as the x-value, so this is incorrect.

(answered this on your other question, but I will put it here too!)

Cada entrada en la primera, segunda, tercera y cuarta tiene solo una salida. En el quinto, 3.3 y 6.6 se ven dos veces como el valor de x, por lo que esto es incorrecto.

(respondí esto en tu otra pregunta, ¡pero también lo pondré aquí!)

3 0

2 years ago

There are three numbers for the combination to the store’s safe. The first number is 14.The other two numbers can be multiplied

Oduvanchick [21]

1, 24; 2, 12; 3, 8; 4, 6. mix and match for the codes but that's like 100+ combinations and I don't have that kind of time sorry

3 0

3 years ago

A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The

TiliK225 [7]

Correct question:

A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The company ships them to restaurants in boxes of 9 salmon, to grocery stores in cartons of 16 salmon, and to discount outlet stores in pallets of 64 salmon. To forecast costs, the shipping department needs to estimate the standard deviation of the mean weight of the salmon in each type of shipment. Complete parts (a) and (b) below.

a. Find the standard deviations of the mean weight of the salmon in each type of shipment.

b. The distribution of the salmon weights turns out to be skewed to the high end. Would the distribution of shipping weights be better characterized by a Normal model for the boxes or pallets?

Answer:

Given:

Mean, u = 44

Sd = 3

The company ships in boxes of 9, cartons of 16 and pallets of 64.

a) For the standard deviations of the mean weight of the salmon in each type of shipment, lets use the formula: $\frac{s.d}{\sqrt{u}}$

i) For the standard deviation of the mean weight of salmon in boxes of 9, we have:

$\frac{s.d}{\sqrt{u}}$

$= \frac{3}{\sqrt{9}}$

$= \frac{3}{3} = 1$

The standard deviation = 1

ii) For the standard deviation of the mean weight of salmon in cartons of 16, we have:

$\frac{s.d}{\sqrt{u}}$

$= \frac{3}{\sqrt{16}}$

$= \frac{3}{4} = 0.75$

Standard deviation = 0.75

iii) For the standard deviation of the mean weight of salmon in pellets of 64, we have:

$\frac{s.d}{\sqrt{u}}$

$= \frac{3}{\sqrt{64}}$

$= \frac{3}{8} = 0.375$

Standard deviation = 0.375

b) The distribution of shipping weights would be better characterized by a Normal model for the pallets, because regardless of the underlying distribution, the sampling distribution of the mean approaches the Normal model as the sample increases.

5 0

3 years ago