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larisa86 [58]
3 years ago
10

PLEASE HELP I WILL GIVE BRAINLIEST TO WHOEVER ANSWERS GOOD PLEASE

Mathematics
2 answers:
Gemiola [76]3 years ago
6 0
8 down is the answer
Vinil7 [7]3 years ago
3 0

Answer:

8 down is the answer brother

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Select two prime numbers that have a sum of 18.
AURORKA [14]

Step-by-step explanation:

option e.5,13

.............

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Which equation matches the graph of the greatest integer function given below?? help pleaze
Alex787 [66]
The correct answer is C
4 0
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Read 2 more answers
What’s the correct why to solve
Vaselesa [24]

x^2-y^2=2\\ \underline{x^2+y^2=4}\\\\ 2x^2=6\\ x^2=3\\ x=-\sqrt3 \vee x=\sqrt3\\\\ 3+y^2=4\\ y^2=1\\ y=-1 \vee y=1\\\\ x\in\{(-\sqrt3,-1),(-\sqrt3,1),(\sqrt3,-1),(\sqrt3,1)\}

So, there are 4 solutions.

6 0
3 years ago
Eloise bought 3 boxes of crackers to share with her friends over the weekend. They ate 1/2 box of crackers on Saturday and 2/3 b
sveticcg [70]

Answer:

C.) 1 5/b boxes

Number of boxes left over

= 3 - 1/2 - 2/3

Convert each  fraction to one in terms of the LCM:

= 18/6 - 3/6 - 4/6

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4 0
3 years ago
I NEED HELP WITH THESE TWO QUESTIONS PLZ DO NOT ANSWER IF YOU CANNOT EXPLAIN THE ANSWER
Murljashka [212]

9514 1404 393

Answer:

  1. asymptotes: x=-6, x=6, y=0; zero: x=0

  2. 20 blue fish

Step-by-step explanation:

1. The vertical asymptotes are where the denominator is zero. It factors as (x-6)(x+6), so will have zeros at x=-6 and x=6.

The horizontal asymptote is at the limit when x goes to infinity. Here, the ratio of highest-degree terms is 6/x, so the value goes to zero as x gets large.

The zero is where the numerator is zero, at x=0.

In summary:

  • vertical asymptotes: x = ±6
  • horizontal asymptote: y = 0
  • zero: (0, 0)

__

2. 60% are red, so 40% are blue. The difference in percentages is 60%-40% = 20%. The percentage of blue fish (40%) is twice the difference (=2×20%), so the number of blue fish is twice the difference in numbers.

  blue fish = 2×10 = 20 fish

<em><u>Check</u></em>

There are then 20+10=30 red fish, so 20+30=50 fish total. Reds are 30/50 = 60% of the total.

<u><em>Additional comment</em></u>

I find it often works well to work with ratios, which I can often do in my head. Other folks like to see equations. Here, we could write equations like ...

  r = 60%(r + b) . . . . reds are 60% of the total

  r - b = 10 . . . . . . . . 10 more reds than blues

We want the value of b, so we can eliminate r by substituting for it:

  r = 10 + b . . . . from the second equation above

  (10 +b) = 0.60((10 +b) + b) . . . . substitute for r

  10 +b = 6 + 1.2b . . . simplify

  4 = 0.2b . . . . subtract b+6

  20 = b . . . . . . multiply by 5 (there are 20 blue fish)

6 0
3 years ago
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