Answer:
is an even function.
Step-by-step explanation:
Recall when it means when a function is even or odd. An even function has the following property:
And an odd function has the following property:
So, let's test some values for cos(x).
Let's use π/3:
From the unit circle, was can see that this is 1/2 (refer to the x-coordinate).
Now, let's find -π/3. This is the same as 5π/3. Thus:
And again from the unit circle, we can see that this is 1/2.
Therefore, despite the negative, the function outputs the same value.
Cosine is an even function.
Notes:
Cosine is an even function and sine is an odd function. It's helpful to remember these as they can help you solve some trig problems!
Answer:
(f o g) (x) = 36x² + 3
(g o f) (x) = 6x² + 18
Step-by-step explanation:
f(x) is x² + 3
g(x) is 6x
(f o g) (x) means for all xs in f replace it with g(x) or 6x
(f o g) (x) = (6x)² + 3 - see 6x is in place of x and 6x is g(x)
(f o g) (x) = 36x² + 3
(g o f) (x) = 6(x² + 3)
(g o f) (x) = 6x² + 18
Vcone=1/3(hpir^2)
Vsphere=(4/3)pir^3
evaluate
vcone=1/3(1pi1^2)=pi/3
vsphere=4/3pi1^3=4pi/3
pi/3 times what=4pi/3
times both sides by 3
pi times what=4pi
divide both sides by pi
1 times what=4
what=4
4 cones
Answer:
140° and 50°
Step-by-step explanation:
The supplement of the angle (180 - x)
The complement of the angle = (90 - x)
(180 -x) = 4(90-x) - 60
180 - x = 360 -4x - 60
180 -x = 300 - 4x
180 - x + 4x = 300
180 + 3x = 300
3x = 120
x = 40
The supplement (180 - x) = 180 - 40 = 140°
The complement (90 - x) = 90 - 40 = 50°
Answer:
5) x = 1, y = -3
6) x = -20, y = 2
7) infinite solutions
8) no solutions
Step-by-step explanation:
5)
y = 5x - 8
y = -6x + 3
5x - 8 = -6x + 3
11x = 11
x = 1
y = 5 - 8
y = -3
6)
2x + 10y = -20
-x + 4y = 28
2x = -20 - 10y
x = - 10 - 5y
-x = 28 - 4y
x = -28 + 4y
-10 - 5y = -28 + 4y
-10 + 28 = 4y + 5y
18 = 9y
2 = y
2x + 20 = -20
2x = -40
x = -20
7)
this has infinite solutions because one equation is a simplified version of the other
8)
this has no solutions because 5 does not equal -5
9)
I can't graph on brainly, hope this helped though
