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3 years ago

15

Sebuah benda bergerak lurus dengan kecepatan 4km/jam selama 1 jam pertama.Pada jam kedua kecepatan dikurangi menjadi setengahnya

,demikian seterusnya,setiap jam kecepatan menjadi setengah kecepatan sdbelumnya.berapa km jarak yang dapat di capai benda tst?

1 answer:

never [62]3 years ago

3 0

A = 4 km/jam
r = 1/2
jarak terjauh
s = a/(1 - r)
s = 4/(1 - 1/2)
<span>s = 8 km</span>

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