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Oksana_A [137]
3 years ago
15

discuss the diets of the ancient Hawaii island people; since that time how has the types of carbohydrates changed and what conse

quences will occur, and are occurring from the consumption of more modern-day carbohydrates?
Health
1 answer:
Brut [27]3 years ago
5 0

Answer:

Taro and poi, breadfruit, sweet potato, bananas, taro tops and some other leafy vegetables, limu, fish and other sea foods etc

Explanation:

Taro and poi, breadfruit, sweet potato, bananas, taro tops and some other leafy vegetables, limu, fish and other sea foods etc are the staple food of the ancient Hawaii island people. Taro is a food having high amount of starch, good source of vitamins A and B, calcium, phosphorus, and iron. The carbohydrates eats at that time comes from totally natural sources which has very beneficial effects on their health while on the other hand, the consumption of modern-day carbohydrates have some adverse effects on the body because these carbohydrates are gained from genetic modified animals and plants.

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Jessica's new diet plan contains 3.3 mg of heme iron and 17.5 mg id non heme iron. what us the amount of biologically available
Hitman42 [59]

1.37mg is a total concentration of iron.

Further Explanation:

Iron is a vitally important element that is required for oxygen transport as a component of hemoglobin. Haemoglobin is composed of <u>two components; heme and globin chain</u>. Heme is further composed of two component; iron and porphyrin ring and globin is a protein chain. Heme part of the hemoglobin helps in binding oxygen component whereas globin chain helps in transport because it is soluble in body fluid. When <u>heme group breaks down it release iron</u> and phosphorus in the body fluid. Iron is obtained from dietary source.

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Biologically available heme can be calculated by the formula given below.

\text{Biologically available}=\dfrac{\text{dietary intake}\times\text{absorption}}{100}

The concentration of heme iron can be calculated by,

\begin{aligned}{\text{Heme iron}}&=\frac{{3.3 \times 15}}{{100}}\\&=0.49{\text{ mg}}\end{aligned}

Calculate the non heme concentration by,

\begin{aligned}{\text{Non - heme iron}}&=\frac{{17.5\times5}}{{100}}\\&=0.875{\text{ mg}}\end{aligned}

Total concentration of iron,

\begin{aligned}{\text{Total iron}}&=0.49+0.875\\&=1.37{\text{ mg}}\end{aligned}

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Answer Details:

Grade: High School

Subjects: Biology

Topic: Dietary Iron

Keywords:

Heme, non heme, iron oxygen, hemoglobin, porphyrin, phosphorus, muscle, tissue, beans, grain, vegetables.

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