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1 year ago

Solve the equation: q –10 = -10

Mathematics

2 answers:

Gala2k [10]1 year ago

5 0

Answer:

No solution

Step-by-step explanation:

The co-efficient, in this case the - 10s, cancel each other out, leaving just q

MrMuchimi1 year ago

3 0

Answer:

Step-by-step explanation:vfsd

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What evidence of climate change on continents supports the theory of continental drift?

77julia77 [94]

Answer:

sorry i was late but the answer is 100% A

Step-by-step explanation:

i just took the test made 100

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2 years ago

Math help please Thanks A lot

babunello [35]

Answer:

2 hours: 3968 [I don't understand the $ sign in the answer box]

At midnight: 12137

Step-by-step explanation:

The bacteria are increasing by 15% every hour. So for every hour we will have what we started with, plus 15% more.

The "15% more" can be represented mathematically with (1 + 0.15) or 1.15. Let's call this the "growth factor" and assign it the variable b. b is (1 + percent increase).

Since this per hour, in 1 hour we'll have (3000)*(1.15) = 3450

At the end of the second hour we're increased by 15% again:

(3450)*(1.15) = 3968.

Each additional hour add another (1.15) factor, If we assign a to be the starting population, this can be represented by:

P = a(1.15)^t for this sample that increase 15% per hour. t is time, in hours.

If a represents the growth factor, and P is the total population, the general expression is

P = ab^t

Using this for a = 3000 and b = 1.15, we can find the total population at midnight after starting at 2PM. That is a 10 hour period, so t = 10

P = (3000)*(1.15)^10

P = 12137

8 0

2 years ago

Helppppp!! What is the inverse of y = 2x^3

Ivan

Answer:

−

(

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√

Step-by-step explanation:

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2 years ago

A credit card company charges 18.6% percent per year interest. Compute the effective annual rate if they compound, (a) annualy,

Darina [25.2K]

Answer:

a) Effective annual rate: 18.6%

b) Effective annual rate: 20.27%

c) Effective annual rate: 20.43%

d) Effective annual rate: 20.44%

Step-by-step explanation:

The effective annual interest rate, if it is not compounded continuously, is given by the formula

$I=C(1+\frac{r}{n})^{nt}-C$

where

C = Amount of the credit granted

r = nominal interest per year

n = compounding frequency

t = the length of time the interest is applied. In this case, 1 year.

In the special case the interest rate is compounded continuously, the interest is given by

$I=Ce^{rt}-C$

(a) Annually

$I=C(1+\frac{0.186}{1})-C=C(1.186)-C=C(1.186-1)=C(0.186)$

The effective annual rate is 18.6%

(b) Monthly

There are 12 months in a year

$I=C(1+\frac{0.186}{12})^{12}-C=C(1.2027)-C=C(0.2027)$

The effective annual rate is 20.27%

(c) Daily

There are 365 days in a year

$I=C(1+\frac{0.186}{365})^{365}-C=C(1.2043)-C=C(0.2043)$

The effective annual rate is 20.43%

(d) Continuously

$I=Ce^{0.186}-C=C(1.2044)-C=C(0.2044)$

The effective annual rate is 20.44%

3 0

2 years ago

When is it best to review your notes

sergey [27]

As soon as possible after the lecture

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2 years ago

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