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Dafna11 [192]
3 years ago
11

A large bag of marbles contains red (R) and blue (B) marbles. Marbles are pulled one at a time, recorded, and placed back in the

bag. Estimate the percentage of blue marbles in the bag.
R R R B R R R R R R B R R R B

A. 60%


B. 80%


C. 25%


D. 20%
Mathematics
1 answer:
ehidna [41]3 years ago
6 0
The answer will be A.
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Find a good suprise way to to tell them

Step-by-step explanation:

Good luck!!!

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A word form for 10,007,000,000,000
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n a survey of 331 customers, 66 say that service is poor. You select two customers without replacement to get more information o
yaroslaw [1]

Answer:

3.93% probability that both say service is poor

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The customers are chosen without replacement, and the order in which they are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

What is the probability that both say service is poor?

Desired outcomes:

Two saying it is poor, from a set of 66. So

D = C_{66,2} = \frac{66!}{2!(66-2)!} = 2145

Total outcomes:

Two customers from a set of 331. So

T = C_{331,2} = \frac{331!}{2!(331-2)!} = 54615

Probability:

p = \frac{D}{T} = \frac{2145}{54615} = 0.0393

3.93% probability that both say service is poor

4 0
3 years ago
Evaluate the function for the given values of x.
galben [10]

Answer:

g(3) = 11

g(-3) = 16

g(-1) =3

Step-by-step explanation:

For g(3)

g(x)= x² +2

g(3) = 3² + 2

g(3) = 9+2

g(3) = 11

For g(-3)

g(x) = -3x + 7

g(-3) = -3(-3) + 7

g(-3) = 9 + 7

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For g(-1)

g(x) = x² + 2

g(-1) = (-1)² +2

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6 0
3 years ago
The quality control manager of a soda manufacturing company wishes to use a significant level of 0.05 to test whether the variab
Alex17521 [72]

Answer: 1.645

Step-by-step explanation:

Given : The quality control manager of a soda manufacturing company wishes to use a significant level of 0.05 to test whether the variabilities in the amount of soda in the company's 16 OZ bottles is more than the variabilities in the company's 12 OZ bottles.

Let \sigma_1^2 represents the variance for 16 OZ bottles and \sigma_2^2 represents the variance for 12 OZ bottles.

The Null and Alternative Hypothesis will be  :-

H_0:\sigma_1^2\geq\sigma_2^2

H_1:\sigma_1^2, since alternative hypothesis is left-tailed , then the test is left-tailed test.

By using the standard normal distribution table for z, the critical value for this hypothesis:-

z_{\alpha}=z_{0.05}=1.645

6 0
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