Well, first we should calculate just how much volume the drum can carry.
The formula we should use is πr^2(h):
π((1.2 ft)^2)(4 ft)
π(1.44 ft^2)(4 ft)
5.76π ft^3 ≈ 18.1 ft^3
Thus is costs:
$22 * 18.1 ft^3
$398.2
Answer:
Les trois nombres sont 5, 6 et 7.
Step-by-step explanation:
Soit x le premier nombre.
x + 1 sera le second et x + 2 sera le troisième.
On pose l'équation :
2x + 3(x + 1) = 4(x + 2)
2x + 3x + 3 = 4x + 8
5x - 4x = 8 - 3
x = 5
area = length times width, so length = area / width
5 1/5 mi^2 5.2 mi^2
Here, length = ------------------- = --------------- = 2.66666... mi = 2 2/3 mi (answer)
1 19/20 mi 1.95 mi
Answer
It would be 3x2 which equals 6
Example-
