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vekshin1
2 years ago
15

Given point P(-8,5) and point Q(-2,1), what is the slope of a line that passes through

Mathematics
1 answer:
olga2289 [7]2 years ago
7 0
To find the slope of a line, use this formula:
m = (y2-y1)/(x2-x1) where m is the slope, and (x1, y1) and (x2, y2) are points.

If I plug points P and Q into the slope formula, we get:

(1-5)/(-2+8) = -4/6 = -2/3

The slope is -2/3
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55,-3

Step-by-step explanation:

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Read 2 more answers
I WILL MARK YOU BRAINLYEST if you answer all of my problems !!!!!!!!!!!
Romashka [77]

First, let's convert each line to slope-intercept form to better see the slopes.

Isolate the y variable for each equation.

2x + 6y = -12

Subtract 2x from both sides.

6y = -12 - 2x

Divide both sides by 6.

y = -2 - 1/3x

Rearrange.

y = -1/3x - 2


Line b:

2y = 3x - 10

Divide both sides by 2.

y = 1.5x - 5


Line c:

3x - 2y = -4

Add 2y to both sides.

3x = -4 + 2y

Add 4 to both sides.

2y = 3x + 4

Divide both sides by 2.

y = 1.5x + 2


Now, let's compare our new equations:

Line a: y = -1/3x - 2

Line b: y = 1.5x - 5

Line c: y = 1.5x + 2

Now, the rule for parallel and perpendicular lines is as follows:

For two lines to be parallel, they must have equal slopes.

For two lines to be perpendicular, one must have the negative reciprocal of the other.

In this case, line b and c are parallel, and they have the same slope, but different y-intercepts.

However, none of the lines are perpendicular, as -1/3x is not the negative reciprocal of 1.5x, or 3/2x.

<h3><u>B and C are parallel, no perpendicular lines.</u></h3>
8 0
3 years ago
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