Answer:
a=6, b=-12, and c=0
Step-by-step explanation:
The standard format for the quadratic formula is ax^2+bx+c (=0).
If we rearrange the numbers given to look like this formula, we will find the values of a, b, and c.
6x^2=12x We can move over the 12x to the other side.
6x^2-12x=0 There is no visible value of c, but since there is no term without a variable, c=0
6x^2-12x+0=0
So a=6, b=-12, and c=0
Answer:
55
Step-by-step explanation:
Let x represent the middle integer. Then the smallest is x-2 and the largest is x+2. Your requirement is that ...
(x-2)/(x+2) > 2/3
3x -6 > 2x +4 . . . . cross multiply
x > 10 . . . . . . . . . . .add 6-2x
The smallest integer satisfying this requirement is x=11. The sum of the 5 integers is 5x = 55.
The smallest sum is 55.
Answer:
-12a + 4b - 8c + 18
Step-by-step explanation:
To do this, you will need to use the Distributive Property. Multiply the number outside of the parenthesis by the terms inside of the parenthesis.
-2(6a - 2b + 4c - 9) becomes:
-12a + 4b - 8c + 18
Hi there, -5*10/9*8=-50/72, -50/72 simplified is -25/36. Therefore, the answer is A. -25/36
