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topjm [15]
3 years ago
8

A snowmobile travels in a straight line.The snow-mobile’s initial velocity is +3.0 m/s.

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
7 0

A) 7 x 0.5 = 3.5 +3.0 = 6.5 m/s

B) 3/.6 = 5, it will take 5 seconds to stop

Troyanec [42]3 years ago
3 0
v_{f}=v_{i}+at
v_{f}=3.0m/s+(0.50m/s^{2})(7.0s)
v_{f}=3+3.5=6.5m/s

v_{f}=v_{i}+at
t=\frac{v_{f}-v_{i}}{a}
t=\frac{0-3}{-0.6}
t=5sec

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A man walking on a railroad bridge is 2/5 of the way along the bridge when he notices a train at a distance approaching at the c
makkiz [27]

Answer:

The Man needs to run at 9 mph

Step-by-step explanation:

Let M stand for the man's speed in mph.  When the man  

runs toward point A, the relative speed of the train with respect  

to the man is the train's speed plus the man's speed (45 + M).  

When he runs toward point B, the relative speed of the train is the  

train's speed minus the man's speed (45 - M).

When he runs toward the train the distance he covers is 2 units.  

When he runs in the direction of the train the distance he covers  

is 3 units. We can now write that the ratio of the relative speed  

of the train when he is running toward point A to the relative speed  

of the train when he is running toward point B, is equal to the  

inverse ratio of the two distance units or

              (45 + M)          3

              -----------  =      ---

              (45 - M)          2

          90+2 M=135-3 M

⇒5 M = 45

⇒ M = 9 mph

The Man needs to run at 9 mph

3 0
3 years ago
Read 2 more answers
A recent study asked U. S. Adults to name 10 historic events that occurred during their lifetime that have had the greatest impa
Nadusha1986 [10]

Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, the parameters are:

z = 2.575, n = 2000, \pi = 0.77

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7458

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7942

The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

More can be learned about the z-distribution at brainly.com/question/25890103

7 0
2 years ago
There are 250 tables total in a cafeteria. There are 150 tables with red tablecloths and 100 tables with white tablecloths. As p
dimaraw [331]

Answer:

60%

Step-by-step explanation:

If there are 250 tables you can multiply it by 4 to work with 1000. This means you have to multiply the other table cloth numbers. 150 x 4 = 600. 100 x 4 = 400. Once you simplify you can get 40 white and 60 red out of 100.  60/100 = 60%.

7 0
2 years ago
Sue bought a pair of jeans and a shirt for $55.75. If the jeans cost $25.25, how much did she pay for the shirt?
givi [52]
Hey there!

In order to find the amount that Sue paid for the shirt, all you have to do is subtract the price of the jeans from the total amount that she paid for the jeans and the shirt. 

55.75 – 25.25 = 30.5

Sue paid $30.50 for the shirt, making your answer A. 

Hope this helped you out! :-)
6 0
3 years ago
For a family party, Tanisha made 2/5 of the dessert. If a total of 40 dessert were brought to the party, how many did Tanisha su
Pavel [41]
16 desserts 8+8+8+8+8= 40 so 2/5 of 40 is 16 
Hope this help Have a great day.
4 0
3 years ago
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