In this situation, you should direct your partner to manually stabilize the women's head, while you quickly visualize her chest to search for signs of breathing. I hope that this helps you!
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I believe the answer is at least two times a week I hope this helps
Answer: hello some details relating to your question is missing below is the missing detail
DNA Sequence= 3’ - TACTAGTTGTGCATT - 5’
Complementary Sequence=5`-ATGATCAACACGTAA-3`
Answer : MINT
Explanation:
The protein ( sequence of amino acids ) that resulted from your Translation is MINT
The m-RNA Produced form the information above is:
5`-AUGAUCAACACGUAA-3`
While the Protein Sequence is Met-Ile-Asn-Thr which can be written as MINT
Answer:
The fraction of heterozygous individuals in the population is 32/100 that equals 0.32 which is the genotipic proportion for these endividuals.
Explanation:
According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the alleles. The genotypic frequencies after one generation are p² (Homozygous for allele p), 2pq (Heterozygous), q² (Homozygous for the allele q). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.
In the exposed example, the r-6 allelic frequency is 0,2. This means that if r-6=0.2, then the other allele frequency (R) is=0.8, and the sum of both the allelic frequencies equals one. This is:
p + q = 1
r-6 + R = 1
0.2 + 0.8 = 1
Then, the genotypic proportion for the homozygous individuals RR is 0.8 ² = 0.64
The genotypic proportion for the homozygous individuals r-6r-6 is 0.2² = 0.04
And the genotypic proportion for heterozygous individuals Rr-6 is 2xRxr-6 = 2 x 0.8 x 0.2 = 0.32
