What is 8.517 in two other forms beside demical

Do you tailgate the car in front of you? About 35% of all drivers will tailgate before passing, thinking they can make the car i

Vesna [10]

Answer:

(a) The histogram is shown below.

(b) E (X) = 4.2

(c) SD (X) = 2.73

Step-by-step explanation:

Let X = r = a driver will tailgate the car in front of him before passing.

The probability that a driver will tailgate the car in front of him before passing is, P (X) = p = 0.35.

The sample selected is of size n = 12.

The random variable X follows a Binomial distribution with parameters n = 12 and p = 0.35.

The probability function of a binomial random variable is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x}$

(a)

For X = 0 the probability is:

$P(X=0)={12\choose 0}(0.35)^{0}(1-0.35)^{12-0}=0.006$

For X = 1 the probability is:

$P(X=1)={12\choose 1}(0.35)^{1}(1-0.35)^{12-1}=0.037$

For X = 2 the probability is:

$P(X=2)={12\choose 2}(0.35)^{2}(1-0.35)^{12-2}=0.109$

Similarly the remaining probabilities will be computed.

The probability distribution table is shown below.

The histogram is also shown below.

(b)

The expected value of a Binomial distribution is:

$E(X)=np$

The expected number of vehicles out of 12 that will tailgate is:

$E(X)=np=12\times0.35=4.2$

Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.

(c)

The standard deviation of a Binomial distribution is:

$SD(X)=np(1-p)$

The standard deviation of vehicles out of 12 that will tailgate is:

$SD(X)=np(1-p)=12\times0.35\times(1-0.35)=2.73\\$

Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.

4 0

3 years ago

Will give first person to answer brainliest!! At a local baseball game, tickets cost $4 for adults and $2 for students. If there

S_A_V [24]

Answer:

let x adult and y student attended

x+y= 94

x=94-y

again

4x+2y = 294 53 adults and 41 student attended

376-4y+2y =294 the event

2y =82

y=41

substituting the value of y in

x+y =94

x= 94-41 = 53

Step-by-step explanation:

8 0

3 years ago

Internet providers: For the data in Exercise 48, estimate the number of Internet plans whose cost is

grandymaker [24]

The answer is c , between 52.43 and 64.20

3 0

3 years ago

Marion Pelk worked 9 days in two weeks. He worked each day and was paid $7.1 an hour. What gross pay he earn for the two weeks?

Andrews [41]

Answer:

$1533.60 !

Step-by-step explanation:

$7.10 per hour needs to be times by 24 (to calculate the pay per day) = $170.40 then times that by 9 = $1533.60 (The pay for 9 days which is coincidently the pay per 2 weeks!

Job done! The answer is $1533.60!

[If I am wrong please message me and tell me]

5 0

3 years ago

Find the number of real zeros of

Amiraneli [1.4K]

Answer:

B

Step-by-step explanation:

Using the determinant to determine the type of zeros

Given

f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is

Δ = b² - 4ac

• If b² - 4ac > 0 then 2 real and distinct zeros

• If b² - 4ac = 0 then 2 real and equal zeros

• If b² - 4ac < 0 then 2 complex zeros

Given

f(x) = (x - 1)² + 1 ← expand factor and simplify

= x² - 2x + 1 + 1

= x² - 2x + 2 ← in standard form

with a = 1, b = - 2, c = 2, then

b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4

Since b² - 4ac < 0 then the zeros are complex

Thus P(x) has no real zeros

6 0

3 years ago