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EastWind [94]
2 years ago
6

Make sure to check the final answer!

Mathematics
2 answers:
kipiarov [429]2 years ago
7 0

Answer:

<u>K=33</u>

Step-by-step explanation:

<u>The objective in this equation is to isolate the unknown variable, or</u><em><u> k.</u></em>

So our first step is to get rid of -11.

To do this, we need to multiply both sides by -11.

<em>K</em>/-11*-11=-3*-11

<u><em>K</em></u><u>=33</u>

Hope this helps!

LenKa [72]2 years ago
5 0

Answer:

k = 33

Step-by-step explanation:

33 ÷ -11 = -3

SIMPLE DIVISION lol

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PLEASE HELP ANSWER WITH ALL STEPS PLS
kupik [55]
Hello.

Question 4:

-2.34n = -12.168
Divide both sides by -2.34;

n = 5.2 is your answer to #4 (Answer choice "C.)"

For Question 5:

-8c = 56
Divide both sides by -8 to solve for c;

c = -7 (remember your signs!) is your answer for #5 (Answer choice "C.)"

\frac{n}{-12.168} = -2; To solve for this, we need to multiply both sides by -12.168 to isolate and solve for our variable.

\frac{n}{-12.168} = -2; Multiply by -12.168

n = 24.336 (A negative multiplied by a negative results in a positive product.);

Your answer for #3 is n = 24.336 (Answer choice "B.)")

I hope this helps!
6 0
3 years ago
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soldier1979 [14.2K]

Answer:

512

Step-by-step explanation:

(a)=a*r^( n − 1)

(9)=2*(-2)^( 9− 1)

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2 years ago
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Answer: 190.52

Step-by-step explanation:

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Write an expression that is equivalent to - 0.5(14a - 22) .
PSYCHO15rus [73]

\textsf{Hey \: there}

<h2>QUESTION</h2>

\mathsf{-0.5(14a - 22)}

<h2>FIRST YOU HAVE TO DISTRIBUTE:</h2>

\mathsf{(-0.5)(14a) + (-0.5)( -22)}

<h2>SOLVING FOR OUR ANSWER</h2>

\mathsf{(0.5)(14a) =  - 7a} \\   \\  \mathsf{( - 0.5)( - 22) = 11}

<h2 /><h2>NEW EQUATION/THE ANSWER YOU WERE LOOKING FOR </h2>

\boxed{ \bf{your \: answer:} \boxed{ \huge \textsf{  \bf- 7a  + 11}}} \checkmark

<h2>GOOD LUCK ON YOUR ASSIGNMENT AND ENJOY YOUR DAY!</h2>

~

\dfrac{\frak{LoveYourselfFirst}}{:)}

<h2>SIDE NOTE: THE DISTRIBUTIVE FORMULA IS</h2>

\text{a(b + c)} \\  \text{a(b) + a(c)} \\ \text{a(b) = ab} \\  \text{a(c) = ac} \\ \text{ \underline{ = ab + ac}}

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