PLS HURRY WILL GIVE BRAINLIEST

Look at this number line.

Lina20 [59]

A it’s a I think ok because I’m new

3 0

3 years ago

Find the volume If the rectangular prism of this 3m,11m,3m and what is the answer

sveta [45]

Answer:

99 m³

Step-by-step explanation:

The volume (V) of a rectangular prism is calculated using the formula

V = lbh

where l is the length, b the breadth and h the height, hence

V = 3 × 11 × 3 = 99 m³

4 0

3 years ago

Answer all of these and I will give you 35 points!!!!!!!!!!!!!!!!!!!!!

aev [14]

9. LCM of 9, 12, and 15 is 180

12. LCM of 15, 18, and 30 is 90

15. LCM of 40 and 1 is 40

16: factors of 24 : 1,2,3,4,6,8,12, and 24

17: factors of 63 : 1, 2, 4, 8, 16, 32 and 64.

18: factors of 50 : 1, 2, 5, 10, 25, and 50

19: LCM of : 3 , 2 , 7 is 42

20: LCM of : 15 , 2 is 30

21: LCM of : 45, 30 is 90

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7 0

3 years ago

Suppose that administrators at a large urban high school want to gain a better understanding of the prevalence of bullying withi

boyakko [2]

Answer:

lower limit =0.261

upper limit =0.369

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Description in words of the parameter p

$p$ represent the real population proportion of people that have experienced bullying

X= 63 people in the random sample that have experienced bullying

n=200 is the sample size required

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that have experienced bullying

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that they were planning to pursue a graduate degree

Confidence interval

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.