We will need to picture for this.
F is number of frogs sold
p is number of Popsicles sold
6f+1.5p=94.50
f+p=36
Rearrange
p=36-f
Substitute
6f+1.5(36-f)=94.5
Reduce
6f+54-1.5f=94.5
4.5f=40.5
F=9
Substitute
9+p=36
P=27
George sold 27 Popsicles and 9 Frogs
<em>The function uses W as the variable but the options show only x's as the variable, so I'm asumming W in the answer</em>
Answer:
0 < W < 50
Correct option: A
Step-by-step explanation:
<u>Domain of functions</u>
Some functions have restricted values of the independent variable x. It can be due to mathematical restrictions, like dividing by 0 or taking the square root of a negative number, of it can be due to practical conditions of the situation being modeled.
In this case, the area of a rectangle is given by the quadratic function.

Since the area of a rectangle cannot be negative (and should be positive, though it could be zero), the practical domain of A is determined when

Taking common factor W

Since W must be positive W>0

Or equivalently


The total interval is

Correct option: A
Please note: The real restriction should be

if we allowed the area to be positive, but I'm providing the most possible correct available option
Answer:
63.6mm
Step-by-step explanation:
According to cosine rule;
AB² = BC²+AC²-2(BC)(AC)cos m<C
Substitute the given values
AB² = 70²+40²-2(70)(40)cos 64
AB² = 4900+1600-5600cos64
AB² = 6500-5600(0.4384)
AB² = 6500-2,454.87
AB² = 4,045.12
AB = √4,045.12
AB = 63.6mm
Hence the length of AB is 63.6mm