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Law Incorporation [45]
3 years ago
7

I do not understand algebra using variables

Mathematics
1 answer:
Dovator [93]3 years ago
5 0
What is the question
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One person can do a certain job in six days, a second person can do the same job in two days, and a third person can do this job
jok3333 [9.3K]
First find their rates...

1/6, 1/2, and 1/3  now combined they will perform the job in one day if:

t/6+t/2+t/3=1  make all have a common denominator

t/6+3t/6+2t/6=6/6 which is equal to:

6t=6 so

t=1

So if they all work together they will complete the job in one day.


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3 years ago
Solve the equation (0°≤A≤360°)<br>a) √3sinA-cosA=√2​
Blizzard [7]

Step-by-step explanation:

√3sinA-cosA=√2

dividing both side by (√3²-1²=2 we get)

√3/2 sinA-1/2.cos A=√2/2

cos 30sinA-sin30cosA=√2/(√2×√2)

sinAcos30-cosAsin30=1/√2

sin(A-30)=sin45,sin(180-45)

therefore

A-30=45,135

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3 years ago
Evaluate the function for x=3; f(x)= -2x+10<br><br> please show your work
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-2x+10
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4

The answer is 4

3 0
4 years ago
Read 2 more answers
The principal amount, $4200, earns 3.6% interest compounded monthly.
svlad2 [7]

Answer:

a)

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

b)

The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 4,200.00 at a rate of 3.6% per year  compounded 12 times per year  over 10 years is $5667.28.

Step-by-step explanation:

a. Write the function that represents the value of the account at any time, t.

The function that represents the value of the account at any time, t

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

where

P represents the principal amount

r represents Annual Rate

n represents the number of compounding periods per unit t, at the end of each period

t represents the time Involve

b) What will the value be after 10 years?

Given

The principal amount  P = $4200

Annual Rate r = 3.6% = 3.6/100 = 0.036

Compounded monthly = n = 12

Time Period = t

To Determine:

The total amount A = ?

Using the formula

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

substituting the values

A\:=\:4200\left(1\:+\:\frac{0.003}{12}\right)^{\left(12\right)\left(10\right)}

\:A\:=\:4200\left(1.0025\right)^{120}

A=5667.28 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 4,200.00 at a rate of 3.6% per year  compounded 12 times per year  over 10 years is $5667.28.

6 0
3 years ago
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