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9514 1404 393
Answer:
- 0 ≤ m ≤ 7
- 0.4541 cm/month; average rate of growth over last 4 months of study
Step-by-step explanation:
<u>Part A</u>:
The study was concluded after 7 months. The fish cannot be expected to maintain exponential growth for any significant period beyond the observation period. A reasonable domain is ...
0 ≤ m ≤ 7
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<u>Part B</u>:
The y-intercept is the value when m=0. It is the length of the fish at the start of the study.
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<u>Part C</u>:
The average rate of change on the interval [3, 7] is given by ...
(f(7) -f(3))/(7 -3) = (4(1.08^7) -4(1.08^3))/4 = 1.08^3·(1.08^4 -1)
≈ 0.4541 cm/month
This is the average growth rate of the fish in cm per month over the period from 3 months to 7 months.
Move constant to the right-hand side and change its sign
2x^2 + 8 = -2 + 7
-2 + 7 = 5
Divide both sides of the equation by
x^2 + 4x = 5/2
Add (4/2^2) to both sides of the equation
x^2 + 4x + (4/2)^2 = 5/2 + (4/2)^2
factor the expression
(x + 4/2)^2 = 13/2
reduce the fraction by 2
(x + 2)^2 = 13/2
now solve equation for x
2x^2 + 8 = -2 + 7
-2 + 7 = 5
Divide both sides of the equation by
x^2 + 4x = 5/2
Add (4/2^2) to both sides of the equation
x^2 + 4x + (4/2)^2 = 5/2 + (4/2)^2
factor the expression
(x + 4/2)^2 = 13/2
reduce the fraction by 2
(x + 2)^2 = 13/2
now solve equation for x