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slamgirl [31]
3 years ago
13

HELP HELP HELP HELPshow the steps too. I'll give BRAINLIEST!​

Mathematics
1 answer:
natali 33 [55]3 years ago
3 0
Move constant to the right-hand side and change its sign

2x^2 + 8 = -2 + 7
-2 + 7 = 5

Divide both sides of the equation by

x^2 + 4x = 5/2

Add (4/2^2) to both sides of the equation

x^2 + 4x + (4/2)^2 = 5/2 + (4/2)^2

factor the expression

(x + 4/2)^2 = 13/2

reduce the fraction by 2

(x + 2)^2 = 13/2

now solve equation for x




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Find all missing angles<br> I need help please
aksik [14]

Answer:

1) 34º

2) 52º

3) 56º

4) 94º

Step-by-step explanation:

let 3 be x

let 1 be y

let 2 be z

let 4 be j

180=86+38+x              56=x

90=56+y                     34=y

180=86+j                     94=j

180=34+z+94              52=z

4 0
2 years ago
Point w is located ar -5,-3 select all of the following that are 5 units from w​
BaLLatris [955]
A and B are both 5 units from it
7 0
3 years ago
PlZZZ HELP<br><br> Which of the following is equal to
stealth61 [152]

Answer:

1st option

Step-by-step explanation:

4 \frac{1}{3} ÷ 2 \frac{3}{5} ( change mixed numbers into improper fractions )

= \frac{13}{3} ÷ \frac{13}{5}

To perform the division

leave 1st fraction, change ÷ to × , turn 2nd fraction ' upside down'

= \frac{13}{3} × \frac{5}{13}

7 0
2 years ago
Read 2 more answers
Write 9/5 as a decimal number.
FrozenT [24]

Answer:

1.8

Step-by-step explanation:

you have to divide 9 from 5 to get 1.8

6 0
3 years ago
Read 2 more answers
The set of the consecutive odd numbers 1, 3, 5, 7, ... , N has a sum of 400. How many numbers are in the set?
Amanda [17]

Well, we could try adding up odd numbers, and look to see when we reach 400. But I'm hoping to find an easier way.

First of all ... I'm not sure this will help, but let's stop and notice it anyway ...
An odd number of odd numbers (like 1, 3, 5) add up to an odd number, but
an even number of odd numbers (like 1,3,5,7) add up to an even number.
So if the sum is going to be exactly 400, then there will have to be an even
number of items in the set.

Now, let's put down an even number of odd numbers to work with,and see
what we can notice about them:

         1, 3, 5, 7, 9, 11, 13, 15 .

Number of items in the set . . . 8
Sum of all the items in the set . . . 64

Hmmm.  That's interesting.  64 happens to be the square of 8 . 
Do you think that might be all there is to it ?

Let's check it out:

Even-numbered lists of odd numbers:

1, 3                                   Items = 2, Sum = 4
1, 3, 5, 7                           Items = 4, Sum = 16
1, 3, 5, 7, 9, 11                 Items = 6, Sum = 36
1, 3, 5, 7, 9, 11, 13, 15 . . Items = 8, Sum = 64 .

Amazing !  The sum is always the square of the number of items in the set !

For a sum of 400 ... which just happens to be the square of 20,
we just need the <em><u>first 20 consecutive odd numbers</u></em>.

I slogged through it on my calculator, and it's true.

I never knew this before.  It seems to be something valuable
to keep in my tool-box (and cherish always).


3 0
3 years ago
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