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slamgirl [31]
3 years ago
13

HELP HELP HELP HELPshow the steps too. I'll give BRAINLIEST!​

Mathematics
1 answer:
natali 33 [55]3 years ago
3 0
Move constant to the right-hand side and change its sign

2x^2 + 8 = -2 + 7
-2 + 7 = 5

Divide both sides of the equation by

x^2 + 4x = 5/2

Add (4/2^2) to both sides of the equation

x^2 + 4x + (4/2)^2 = 5/2 + (4/2)^2

factor the expression

(x + 4/2)^2 = 13/2

reduce the fraction by 2

(x + 2)^2 = 13/2

now solve equation for x




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25x power square - 36 y power square​
finlep [7]

\implies {\blue {\boxed {\boxed {\purple {\sf {  (5x + 6y)(5x - 6y) }}}}}}

\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}

={25x}^{2}  - 36 {y}^{2}

=  ({5 \times 5)x}^{2}  -  (6 \times 6){y}^{2}

=  ({5x})^{2}  -(  {6y})^{2}

= (5x + 6y)(5x - 6y)

<h3><u>Note</u>:</h3>

{a}^{2}  -  {b}^{2}  = (a + b)(a - b)

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}

3 0
3 years ago
Can you help me please? I would appreciate it ❤️❤️
lianna [129]
The answer is 9
You divide 143 % 11 to get 13. 13 is the number they make an hour, so if you divide 117 % 13 you will get 9.
8 0
2 years ago
Sally has 71 peppermints. Bernard has p fewer peppermints than Sally. Write an expression that shows how many peppermints Bernar
satela [25.4K]

an expression is:

y = 71 - p

4 0
1 year ago
Read 2 more answers
A team of three students are working on a language-learning app; they need to develop 300 micro-lessons and 300 micro-tests befo
Olegator [25]

Answer: a) 15 b)

Step-by-step explanation:

Let X be the number of days:

a)

For LESSONS:

Jordan does 10 / day ( 10*X)

Marco 5 / day ( 5*X)

Junyi 5 / day ( 5*X)

For TESTS:

Jordan does 5 / day ( 5*X)

Marco 10 / day ( 10*X)

Junyi 8 / day ( 8*X)

for each they need a total of 300

a) 10X+5X+5X=300 => 20X = 300 => X = 15 days for the lessons

b) 5X+10X+8X = 300 => 23X = 300 => X = 13.04 days for the tests

so they need 15 days to finish both tasks

now if Junyi gets sick we just eliminate his contribution

a) 10X+5X=300 => 15X = 300 => X = 20 days for the lessons

b) 5X+10X = 300 => 15X = 300 => X = 20 days for the tests

so in 20 days they will finish without him

If jordan works 10 hours a day, we just replace him with 10/24

a) 10(10/24)+5X+5X= 300 => X = 29.58 days for the lessons

b) 5(10/24)+10X+8X = 300 => X = 16.51 days for the tests

so at the end to complete both tasks they need 29.58 days

4 0
3 years ago
A group of researchers are interested in the possible effects of distracting stimuli during eating, such as an increase or decre
Dmitry [639]

Using the t-distribution, it is found that since the p-value of the test is of 0.0302, which is <u>less than the standard significance level of 0.05</u>, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

At the null hypothesis, it is <u>tested if the consumption is not different</u>, that is, if the subtraction of the means is 0, hence:

H_0: \mu_1 - \mu_2 = 0

At the alternative hypothesis, it is <u>tested if the consumption is different</u>, that is, if the subtraction of the means is not 0, hence:

H_1: \mu_1 - \mu_2 \neq 0

Two groups of 22 patients, hence, the standard errors are:

s_1 = \frac{45.1}{\sqrt{22}} = 9.6154

s_2 = \frac{26.4}{\sqrt{22}} = 5.6285

The distribution of the differences is has:

\overline{x} = \mu_1 - \mu_2 = 52.1 - 27.1 = 25

s = \sqrt{s_1^2 + s_2^2} = \sqrt{9.6154^2 + 5.6285^2} = 11.14

The test statistic is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{25 - 0}{11.14}

t = 2.2438

The p-value of the test is found using a <u>two-tailed test</u>, as we are testing if the mean is different of a value, with <u>t = 2.2438</u> and 22 + 22 - 2 = <u>42 df.</u>

  • Using a t-distribution calculator, this p-value is of 0.0302.

Since the p-value of the test is of 0.0302, which is <u>less than the standard significance level of 0.05</u>, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

A similar problem is given at brainly.com/question/25600813

4 0
3 years ago
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