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2 years ago

11

What is the midpoint of 23.8 and 23.7?

2 answers:

Strike441 [17]2 years ago

7 0

Answer:

23.75

Step-by-step explanation:

nydimaria [60]2 years ago

3 0

Answer:

23.75

Step-by-step explanation:

1. 23.8 - 23.7 = 0.1

2. 0.1 ÷ 2 = 0.05

3. 0.05 + 23.7 = 23.75

this works because to find the middle of two numbers (in this explanation 10 and 20), you have to subtract the larger one from the smaller one (20 - 10 = 10) and take your sum and divide it by two (10 ÷ 2 = 5) and then add it back to the smaller number (5 + 10 = 15 = 1/2 the midpoint of 10 and 20)

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3 years ago

(2.75 x 107) + (1.23 x 108) simplify

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2 years ago

Solve 5x^2 − 3x + 17 = 9.

Vedmedyk [2.9K]

Answer:

The roots of the equation are x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

or

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = $\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = $\frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}$

or

x = $\frac{3\pm\sqrt{9-160}}{10}$

or

x = $\frac{3+\sqrt{-151}}{10}$ and x = $\frac{3-\sqrt{-151}}{10}$

or

x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

here i = √(-1)

Hence,

The roots of the equation are x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

and there are no real roots of the equation given above

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2 years ago