Which expression is equal to 75√ ? 75√25 355√ 75√5 4935√

At first public inquiry showed there were 637000 women motorcyclists in the US up from 437000 just 8 years ago before it. Find t

dimaraw [331]

I would say to do 637000-437000, which is 200000, and then do 200000/637000. You get 0.314, and the percentage of that in hundreds is 31%.

6 0

3 years ago

Children gender. a certain couple is equally likely to have either a boy child or a girl child. if the family has four children,

rusak2 [61]

D. at least two girls

6 0

3 years ago

Identify the figure that portrays the translation of the given preimage as indicated by the direction arrow.

ladessa [460]

The parallelogram will translate along the arrow and reach the head of the arrow.

The translation is a category of motion in which one body moves along towards a particular direction and reaches a particular point.

In translation, the rotational motion is not present. Also, the translational motion is a one-dimensional motion.

In the given figure, the parallelogram is present at the tail of the arrow.

The arrow depicts the direction of the translational motion.

So, the parallelogram will reach the end of the arrow as shown in the picture present in the attachment.

For more explanation about translation or rotation, refer to the following link:

hhttps://brainly.com/question/9032434

#SPJ10

6 0

2 years ago

1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.

xxTIMURxx [149]

First, rewrite the equation so that y is a function of x :

$x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}$

(If you were to plot the actual curve, you would have both $y=x^{2/3}$ and $y=-x^{2/3}$ , but one curve is a reflection of the other, so the arc length for 1 ≤ x ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

$\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx$

We have

$y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}$

Then in the integral,

$\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx$

Substitute

$u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx$

This transforms the integral to

$\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du$

and computing it is trivial:

$\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)$

We can simplify this further to

$\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}$

7 0

3 years ago

When the number k is multiplied by 5, the result is the same as when 5 is added to k. What is the value of k?

Bas_tet [7]

K=1.25 or 5/4
5k=k+5
-5k+k+5=0
-4K+5=0
-4K=-5
5/4=k

5 0

3 years ago

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