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DedPeter [7]
3 years ago
14

Solve for x. x/3≤−6 A. x≥−18 B. x≤−18 C. x≥−2 D. x≤−2

Mathematics
2 answers:
Akimi4 [234]3 years ago
5 0

Answer:

Step-by-step explanation:

x/3 ≤ -6

x ≤ -18

answer is B

Kisachek [45]3 years ago
4 0

Answer:

B

Step-by-step explanation:

it is simple easy..first you have to through your 3 become times with -6,then you have your answer

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Step-by-step explanation:

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What is the area of the space that Nadia has shown for scrapbooking ​
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Step-by-step explanation:

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Please help me I put 100 points for anyone who helps me
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Answer:

a)

<u>The discount id 40%, so the function is:</u>

  • d = 0.4p

b)

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  • p = 300 ⇒ d = 120
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  • p = 500 ⇒ d = 200

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What is the correct answer to a+ny=n, solving for n?
AysviL [449]
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6 0
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suppose a parabola has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1). Write the eq
lesya [120]

Answer:

<h3>            f(x) = - 3(x + 8)² + 2</h3>

Step-by-step explanation:

f(x) = a(x - h)² + k   - the vertex form of the quadratic function with vertex    (h, k)

the<u> axis of symmetry</u> at<u> x = -8</u> means h = -8

the <u>maximum height of 2</u> means  k = 2

So:

f(x) = a(x - (-8))² + 2

f(x) = a(x + 8)² + 2   - the vertex form of the quadratic function with vertex   (-8, 2)

The parabola passing through the point (-7, -1) means that if x = -7 then        f(x) = -1

so:

    -1 = a(-7 + 8)² + 2

 -1 -2 = a(1)² + 2 -2

      -3 = a

Threfore:

The vertex form of the parabola which has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1) is:

                                 <u>f(x) = -3(x + 8)² + 2</u>

8 0
3 years ago
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