The bell curve attached below shows the normal distribution of the data.
We are looking the value of X such as the area to its left gives the probability of 0.75
We first need the z-score which we can obtain by reading from the z-table (as shown in the second picture below)
The z-score is = 0.7734
Then we use the following formula to work out X
z-score = (X - Mean) ÷ Standard Deviation
0.7734 = (X - 100) ÷ 15
0.7734×15 = X - 100
11.601 = X - 100
X = 11.601 + 100
X = 111.601 ≈ 112
Hence the third quartile is 112
Formulas tab > in the Function Library group, click Lookup & Reference button, select VLOOKUP. Type A3 in the Lookup_value argument box. Type Abbreviation in the Table_array argument box. Type 2 in the Col_num argument box. Type False in the Rang_lookup box. Click OK, is this what you were looking for?
Simply view this formula as an equation and solve for R
This would look like:
V=IR
V/I=R/I
V/I=R
ANSWER
R=v divided by I
Circumference of a circle is 2πr where r is radius of a circle.
2*3.14*7=43.96 almost 44 inches in whole number where π=3.14
I am pretty sure it’s 14 I think but i don’t know for sure