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DedPeter [7]
3 years ago
14

Solve for x. x/3≤−6 A. x≥−18 B. x≤−18 C. x≥−2 D. x≤−2

Mathematics
2 answers:
Akimi4 [234]3 years ago
5 0

Answer:

Step-by-step explanation:

x/3 ≤ -6

x ≤ -18

answer is B

Kisachek [45]3 years ago
4 0

Answer:

B

Step-by-step explanation:

it is simple easy..first you have to through your 3 become times with -6,then you have your answer

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(x3 + 3x² + x + 6) + (x - 1)
DaniilM [7]

Answer:

x^3 + 3x^2 + 2x + 5

Step-by-step explanation:

combine like-terms

3 0
3 years ago
90 POINTS!!!!PLZ HURRY WILL GIVE BRAINIEST <br> Use trigonometry to find the measure of x
Lapatulllka [165]

Answer:

nein

Step-by-step explanation:

6 0
3 years ago
Determine which system goes with what
Gnom [1K]

Answer:

  a, c, b, none

Step-by-step explanation:

Since we're solving a number of simultaneous equations, and/or evaluating them for a variety of points, it makes a certain amount of sense to use a tool capable of simplifying the process.

The attached shows plots of the lines and their points of intersection. Each pair is plotted in the same color.

The solutions to the equations are ...

  (3, 7) -- a (red)

  (2, -1) -- c (green)

  (4, 14) -- b (blue)

  (4, 20) -- none (not on any line)

__

You can also choose pairs by trying the points in the equations. Once we have settled on a solution, we don't need to try that set of equations anymore.

a with (3, 7): 7 = 4(3) -5 . . . . true

b with (2, -1): -1 = -7(2) +42 . . . . false

c with (2, -1): -1 +12(2) = 23 . . . . true

b with (4, 14): 14 = -7(4) +42 . . . . true

d with (4, 20): 2(20) +8(4) = 52 . . . . false

This tells us the likely answers are a, c, b, none.

_____

<em>Additional comment</em>

When the equation for a line is written in "general form", its expression is ...

  ax +by +c = 0

We know that a product will be zero if and only if one or both of the factors is zero. That lets us use the graphing calculator to plot both lines of a system of equations using a single equation.

Starting from (line 1 expression) = 0, and (line 2 expression) = 0, we form the product (line 1 expression)(line 2 expression) = 0. The graphing calculator does the rest, showing both lines, their x- and y-intercepts, and their point of intersection.

We used this method here simply for the purposes of (a) writing fewer equations, and (b) making both lines of a system the same color.

__

Writing systems of equations in general form also has the benefit that it makes using the "cross multiplication method" of solution easy to use--in the event you want to solve the systems algebraically.

Here's more on the cross multiplication method of solving a pair of linear equations: brainly.com/question/26397343

3 0
3 years ago
Sole by substitution.<br> -3x+2y=16<br> X-2y=-12
bekas [8.4K]
Answer: (-2,5)

Step 1: Rewrite equations

-3x+2y=16

x-2y=-12

Step 2: Changing the second equation

With substitution, you have to already have the equation to solve for the specific variable (ex: x=y+1;y=x+1). Since the equation doesn’t give us one, we can flip the second equation to give us this.

Let’s add 2y on both sides.

x-2y=-12
+2y +2y
_________
x=2y-12

Now we have the equation to solve for x!

Step 3: Substituting

Now we need to substitute x into the first equation. Let’s do this now.

-3(2y-12)+2y=16

Step 4: Solving for y

-3(2y-12)+2y=16

*distribute*

-6y+36+2y=16

*combine like terms*

-4y+36=16

*subtract 36 on both sides*

-4y=-20

*divide both numbers by -4*

y=5

This is y! Now we need to solve for x.

Step 5: Solving for x

To find x, let’s just substitute y into the equation and solve

x=2y-12

x=2(5)-12

x=10-12

x=-2

Step 6: Ordered pair

(X,y) —> (-2,5)


This is your answer! Hope this helps comment below for more questions :)
6 0
3 years ago
Read 2 more answers
20(base three)-11(base three) . Carry out the operation in binary system​
bija089 [108]

20₃ - 11₃ = 20₃ - 10₃ - 1₃

… = 10₃ - 1₃

… = 2₃

Put another way, we "borrow a 1" from the 3¹ digits place:

20₃ = 1(3)₃ - 11₃ = 2₃

But this is just the number 2 (in base 10), which in base 2 would be 10₂.

4 0
3 years ago
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