You see how many times 6 can fit into 13 (two), and see how many 6ths are left (one). So the answer would be 2 and 1/6.
Answer:
0.9986
Step-by-step explanation:
- Prob (Machine tool actually fails) = 0.04
- So, Prob (Machine tool actually functions) = 1 - 0.04 = 0.96
- Prob (functional machine tool claimed fail) = 0.08
- So, Prob (functional machine tool claimed functional) = 1- 0.08 = 0.92
- Prob (fail machine tool claimed fail) = 0.97
- So, Prob (fail machine tool claimed functional) = 1- 0.97 = 0.03
Prob A: P [Machine tool indicated (claimed) functional] :- Functional machine tool or fail machine tool claimed functional = (0.96)(0.92) + (0.04)(0.03) = 0.8844
Prob B: P [Machine tool actually function when passed by QAs] = (0.96)(0.92) = 0.8832
Prob (A given B) = P (A & B) / P (A)
= 0.8832 / 0.8844 = 0.9986
Blake must score an average of at least a 93 on his second semester to be able to have an average of 90 for both semesters.
To solve this equation isolate the variable and add 2/3 to both sides
Answer:
4 and 9
Step-by-step explanation:
I am going to use an upper case E for the symbol in the answers. The E symbol means "is a member of set..."
So " 1 E A " means "1 is a member of set A."
And " 4 E A" means "4 is a member of set A.
Now at the beginning of the question they told you what numbers were in which sets. 1 through 9 are in set U. But only 4 and 9 are in set A. The contents of the set are listed in between a pair of grouping symbols { } that are kind of squiggly brackets. That's how you know what is in the set.
Since set A only contains 4 and 9, those are your two correct answers:
"4 E A" AND "9 E A"
