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2 years ago

How many times can I access to questions and answers if I don't use Brainly Plus?

Mathematics

2 answers:

alexira [117]2 years ago

6 0

Answer:

INIFINITE MAN

Step-by-step explanation:

They just add some stuff, but I would not waste my money for that :)

Otrada [13]2 years ago

4 0

Step-by-step explanation:

Brainly Plus just gets rid of ads im pretty shure sorry if im wrong

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The ratio of the length of the corresponding sides of two rectangles is 5:8. The area of the smaller rectangle is 130 m2. To the

xxMikexx [17]

I think the answer is 332.8 cm^2

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3 years ago

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Help pls its too hard

damaskus [11]

Answer:

3/4 cups of coconut oil.

Step-by-step explanation:

1/3 * 3 = 3/3 = 1

1/4 * 3 = 3/4

So it would be

3/4

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2 years ago

I neeed help please

Sliva [168]

Answer:

The greater unit rate of the two functions is the first function shown by the table and the greater y intercept is the second function shown by the graph.

Step-by-step explanation:

Find the slope of both equations

(15-5)/(5-0) = 2

(6-0)/(0+4) = 3/2

2>3/2

y-intercept is where the function crosses the y axis, function 1 y-intercept is 5 and the y-intercept of function 2 is 6, 6>5

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3 years ago

I need help solving this equation

solmaris [256]

Answer:

-765

Step-by-step explanation:

-2-7 * 109

-2 - 763

-765

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2 years ago

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Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

How many times can I access to questions and answers if I don't use Brainly Plus? ​

How many times can I access to questions and answers if I don't use Brainly Plus?