The answer for the question shown above is: <span>B. Both powers should be in the dominator with positive exponent.
The explanation is shown below:
1. You have the following expression given in the problem above:
x⁻3y⁻9
2. The negative exponents indicates that </span>x⁻3y⁻9 should be in the denominator with positive exponents. Therefore, you have:
x⁻3y⁻9=1/x^3y^9
Answer:
This was posted a long time ago Sorry I'm super late!
Step-by-step explanation:
I assume you already completed this question but I am trying to move up a level and have full points yet still need more brainliest so I was hoping you could still mark me brainliest? Its fine if not no worries. Have an amazing day and a spectacular spring break!
Please mark brainliest!
Remember your worth! Have a great day and year!
Step-by-step explanation and answer:
To understand this problem, you must first understand the definition of domain and range. Domain is all possible x values (possible input), and range is all possible y values (possible output). Based on this, we can now sort the terms as the following:
Domain
- Independent variable
- Input value
- X-value
Range
- Dependent variable
- Y-value
- Output value
Hope this helps!!
Answer:
vfhgfhfjhfvhjgv
Step-by-step explanation:
Answer:
D)Yes, because the difference in the means in the actual experiment was more than two standard deviations from 0.
Step-by-step explanation:
We will test the hypothesis on the difference between means.
We have a sample 1 with mean M1=18.2 (drug group) and a sample 2 with mean M2=15.9 (no-drug group).
Then, the difference between means is:
If the standard deviation of the differences of the sample means of the two groups was 1.1 days, the t-statistic can be calculated as:
The critical value for a two tailed test with confidence of 95% (level of significance of 0.05) is t=z=1.96, assuming a large sample.
This is approximately 2 standards deviation (z=2).
The test statistict=2.09 is bigger than the critical value and lies in the rejection region, so the effect is significant. The null hypothesis would be rejected: the difference between means is significant.
