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UkoKoshka [18]
3 years ago
8

10) 3x + x + x + x - 3 - 2 = 7 + x + x In the equation above, what is the value of x?

Mathematics
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

Step-by-step explanation:

x=3

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The sales tax for an item was $19.20 and it costs $480 before tax. Find the sales tax rate. Write your answer as a percentage
Zigmanuir [339]

Answer:

sales tax rate = 4%

Step-by-step explanation:

In this problem formula to express one term in percentage is used

To express x as percentage of y is given by (x/y*100) %

______________________________________________

Cost of item = $480

sales tax = $19.20

we have to find sales tax rate.

sales tax rate is percentage of cost price which will levied as tax .

thus, we have to find sales tax as percentage of cost price.

using the percentage cost as given above

sales tax as percentage = sales tax/ cost of item *100

sales tax as percentage = 19.20/480 *100 = 4%

Thus, sales tax rate is 4%.

It means that if cost price of item is $100 then $4 will be the sales tax for the item.

5 0
3 years ago
What transformation of Figure 1 results in Figure 2.? A dilation of Figure 1 results in Figure 2.
sergiy2304 [10]

A dilation is when the shape changes I. Size

3 0
3 years ago
Students in Mrs. Garcia’s class were practicing drawing nets. She gave them the three-dimensional figure shown. Alina drew the n
NNADVOKAT [17]

Answer:

both nets are correct

Step-by-step explanation:i took the Assignment and got it right

6 0
3 years ago
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6 0
3 years ago
What is tan(θ/2), when tan(θ) = 4/3 and when π < θ < 3π/2?
Tamiku [17]
Tan (Ф/2)=⁺₋√[(1-cosФ)/(1+cosФ)]
if π<Ф<3π/2;
 then,  Where is Ф/2??
π/2<Ф/2<3π/4; therefore Ф/2 is in the second quadrant; then tan (Ф/2) will have a negative value.

tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]

Now, we have to find the value of cos Ф.
tan (Ф)=4/3
1+tan²Ф=sec²Ф
1+(4/3)²=sec²Ф
sec²Ф=1+16/9
sec²Ф=(9+16)/9
sec²Ф=25/9
sec Ф=-√(25/9)        (sec²Ф will have a negative value, because Ф is in the        sec Ф=-5/3                                 third quadrant).

cos Ф=1/sec Ф
cos Ф=1/(-5/3)
cos Ф=-3/5

Therefore:

tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
tan(Ф/2)=-√[(1+3/5)/(1-3/5)]
tan(Ф/2)=-√[(8/5)/(2/5)]
tan(Ф/2)=-√4
tan(Ф/2)=-2

Answer: tan (Ф/2)=-2; when tan (Ф)=4/3


3 0
3 years ago
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