Answer:
The relation is not a function
The domain is {1, 2, 3}
The range is {3, 4, 5}
Step-by-step explanation:
A relation of a set of ordered pairs x and y is a function if
- Every x has only one value of y
- x appears once in ordered pairs
<u><em>Examples:</em></u>
- The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
- The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
- The domain is the set of values of x
- The range is the set of values of y
Let us solve the question
∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}
∵ x = 1 has y = 3
∵ x = 2 has y = 3
∵ x = 3 has y = 4
∵ x = 2 has y = 5
→ One x appears twice in the ordered pairs
∵ x = 2 has y = 3 and 5
∴ The relation is not a function because one x has two values of y
∵ The domain is the set of values of x
∴ The domain = {1, 2, 3}
∵ The range is the set of values of y
∴ The range = {3, 4, 5}
- 8x - 9 = - 21
Add 9 to both sides:
- 8x = - 12
Divide both sides by - 8:
x = -12/-8
x = -3/-2
x = 3/2 OR 1.5
Hope this answer helps :)
Answer:
the answer is that both x and y are acute
Answer:
The answer is 4.5 and 9/2
Step-by-step explanation:
First
54 / 12 = 4.5
Then
Change it into a fraction
Write is fraction form 4.5 / 1
Multiply both numerator and denominator by 10 for every number after the decimal point
4.5 × 10
1 × 10
Which will equal 45/10
Then Reduce the fraction gives 9/2
Answer:
4
Step-by-step explanation:
-7 squared by the number 4 = -28